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Leviafan [203]
2 years ago
7

1. Which of these can be used to observe the field of the

Physics
2 answers:
irina [24]2 years ago
8 0
The answer is b ( i think don’t quote me)
Levart [38]2 years ago
8 0

Answer:

B. iron fillings

Explanation:

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Compare and contrast chemical reactions and nuclear reactions in terms of particles involved . Select all the statements that ap
Anna11 [10]

Answer:

. A chemical reaction is the rearranging of atoms to form new substances. E=mc^ aleph

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3 years ago
Define force ? ☹❣️️ Degine weight? ​
mylen [45]

Explanation:

force is anything that allows a body to be in motion..

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3 years ago
An overhead door is guided by wheels at a and b that roll in horizontal and vertical tracks. when θ = 40°, the velocity of wheel
Karo-lina-s [1.5K]

I think the situation is modeled by the scenario in the attached image. Some specific values seem to be missing (like the height of door d)...

The door forms a right triangles that satisfies

\tan\theta=\dfrac ab\implies\sec^2\theta\dfrac{\mathrm d\theta}{\mathrm dt}=\dfrac{b\frac{\mathrm da}{\mathrm dt}-a\frac{\mathrm db}{\mathrm dt}}{b^2}

We also have

\tan\theta=\dfrac ab\implies\cos\theta=\dfrac bd

so if you happen to know the height of the door, you can solve for b and a.

d is fixed, so

a^2+b^2=d^2\implies2a\dfrac{\mathrm da}{\mathrm dt}+2b\dfrac{\mathrm db}{\mathrm dt}=0\implies\dfrac{\mathrm da}{\mathrm dt}=-\dfrac ba\dfrac{\mathrm db}{\mathrm dt}

We can solve for the angular velocity \dfrac{\mathrm d\theta}{\mathrm dt}:

\dfrac{\mathrm d\theta}{\mathrm dt}=\cos^2\theta\dfrac{b\left(-\frac ba\frac{\mathrm db}{\mathrm dt}\right)-a\frac{\mathrm db}{\mathrm dt}}{b^2}=-\dfrac1a\dfrac{\mathrm db}{\mathrm dt}

At the point when \theta=40^\circ and \dfrac{\mathrm db}{\mathrm dt}=1.8 ft/s, we get

\dfrac{\mathrm d\theta}{\mathrm dt}=-\dfrac{1.8}a\dfrac{\rm deg}{\rm s}=-\dfrac{1.8}{d\sin40^\circ}\dfrac{\rm deg}{\rm s}

6 0
3 years ago
As an tempature decreases what happens to the rate of radiation?
Firlakuza [10]
As the temperature decreases, the rate of radiation goes down, but the radiation exists as long as the temperature is above the absolute zero, which is actually 0 Kelvin. 0 Kelvin equals -273°C or -460°F. All objects in the world radiate if above that temperature.
5 0
3 years ago
5. Steve is driving in his car to take care of some errands. The first errand has him driving to a location 2 km East and 6 km N
Sever21 [200]

Answer:

gshshs

Explanation:

hshsksksksbsbbshd

3 0
3 years ago
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