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3 years ago

Giving me the points are enough

Physics

1 answer:

N76 [4]3 years ago

7 0

Answer:

the product of mass and velocity

....in my syllabus

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A standing wave on a string that is fixed at both ends has frequency 80.0 Hz. The distance between adjacent antinodes of the sta

Bingel [31]

Answer:

Speed of the wave in the string will be 3.2 m/sec

Explanation:

We have given frequency in the string fixed at both ends is 80 Hz

Distance between adjacent antipodes is 20 cm

We know that distance between two adjacent anti nodes is equal to half of the wavelength

So $\frac{\lambda }{2}=20cm$

$\lambda =40cm$

We have to find the speed of the wave in the string

Speed is equal to $v=\lambda f=0.04\times 80=3.2m/sec$

So speed of the wave in the string will be 3.2 m/sec

4 0

3 years ago

A spherical snowball is melting in such a way that its diameter is decreasing at a rate of 0.3cm per minute. At what rate in cub

Scorpion4ik [409]

Answer: 12.15π cm³/min

Explanation:

Given,

Diameter, d = 9 cm

Volume of a sphere, v = 4/3.π.r³

dD/dt = -0.3 cm/min (the negative sign is because it is decreasing)

Volume = 4/3.π.(d/2)³

Volume = 4/3.π.(d³/8)

Volume = 1/3.π.(d³/2)

Volume = 1/6.π.d³

dV/dt = 1/2.π.d².(dD/dt), substituting the value of dD/dt onto this, we have

dV/dt = 1/2.π.9².(-0.3)

dV/dt = 1/2.π.81.-0.3

dV/dt = 1/2.π.-24.3

dV/dt = -12.15π cm³/min

Thus, the volume of the snowball is changing at 12.15π cm³/min

5 0

3 years ago

Read 2 more answers

What is the distance traveled when you stretch a rubber band 15 cm?

mrs_skeptik [129]

Answer:

15 cm

Explanation:

common sense

3 0

3 years ago

An object's distance from a converging lens is 3.78 times the focal length. a) Determine the location of the image. Express the

Romashka-Z-Leto [24]

Answer:

a) v=1.36f

b)m=.36

c) real

d) Inverted

Explanation:

In this question we have given,

object distance from converging lens,u=-3.78f

focal length of converging lens,=f

we have to find location of image,v=?

and magnification,m=?

we know that u, v and f are related by following formula

$\frac{1}{f} =\frac{1}{v}- \frac{1}{u}$ .............(1)

put values of f u in equation (1)

we got,

$\frac{1}{f} =\frac{1}{v}- \frac{1}{-3.78f}$

$\frac{1}{f}-\frac{1}{3.78f} =\frac{1}{v}$

$\frac{2.78}{3.78f} =\frac{1}{v}$

v=1.36f

b) Magnification, $m=\frac{v}{u} \\m=\frac{1.36f}{3.78f}\\m=.36$

Here the object is located further away from the lens than the focal point therefore image is real image and inverted.

d) image is inverted

7 0

3 years ago

What is the standard unit of velocity

Bond [772]

Answer:

Explanation:

Meters per second

7 0

3 years ago

Read 2 more answers

Giving me the points are enough ​

Giving me the points are enough