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ahrayia [7]
4 years ago
12

The process of an atom releasing energy when it moves to a lower energy state is called

Chemistry
1 answer:
Inga [223]4 years ago
4 0
The process of an atom releasing energy when it moves to a lower energy state is called emission.
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Solve this problems using the equation: C = λ x ν........ A microwave oven emits radiation at a wavelength of 5.00 x 10e-5 m. Wh
stira [4]

Answer:

c = λ x ν

v =c/λ=(3*10e8)/(5.00 x 10e-5)=6000000000000

f = v/λ =6000000000000/5.00 x 10e-5=120000000

Explanation:

4 0
3 years ago
over a 12.3 minuete period 5.13 E-3 moles of F2 gas effuses from a contaier. How many moles of CH4 gas could effuse from from th
Aleonysh [2.5K]

Answer : The moles of methane gas could be, 7.90\times 10^{-3}mol

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}

[\frac{(\frac{n_1}{t_1})}{(\frac{n_2}{t_2})}]=\sqrt{\frac{M_2}{M_1}}

where,

R_1 = rate of effusion of fluorine gas

R_2 = rate of effusion of methane gas

n_1 = moles of fluorine gas = 5.13\times 10^{-3}mol

n_2 = moles of methane gas = ?

t_1=t_2 = time = 12.3 min  (as per question)

M_1 = molar mass of fluorine gas  = 38 g/mole

M_2 = molar mass of methane gas = 16 g/mole

Now put all the given values in the above formula 1, we get:

[\frac{(\frac{5.13\times 10^{-3}mol}{12.3min})}{(\frac{n_2}{12.3min})}]=\sqrt{\frac{16g/mole}{38g/mole}}

n_2=7.90\times 10^{-3}mol

Therefore, the moles of methane gas could be, 7.90\times 10^{-3}mol

8 0
3 years ago
At 304 K, a 9.6 L tank contains 1.9 moles of H2 gas under an unknown pressure in atm. What is the pressure of the gas in the tan
ratelena [41]

Answer:

The pressure is 4.939 atm

Explanation:

As we know

PV = nRT

where P is the pressure

V is the volume

n is the total number of moles

R is the gas constant

and T is the temperature

Substituting the given values we get -

P * 9.6 = 1.9 * 0.0821 *304\\P = 47.420/9.6\\P = 4.939

The pressure is 4.939 atm

8 0
3 years ago
Read 2 more answers
Balancing equations
Bad White [126]
Make sure you numbers with variable are on one side and the numbers 

7 0
4 years ago
2 NaOH + H2SO4 → 2 H2O + Na2SO4<br> How many grams of water are produced from 203.50 grams of H2S04?
ddd [48]

Answer:

m_{H_2O}=74.8gH_2O

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible to realize there is a 1:2 mole ratio of sulfuric acid to water; thus, given the mass of the former and its molar mass (98.07 g/mol), it is possible to determine the mass of produced water as shown below:

m_{H_2O}=203.50gH_2SO_4*\frac{1molH_2SO_4}{98.07gH_2SO_4}*\frac{2molH_2O}{1molH_2SO_4}  *\frac{18.02gH_2O}{1molH_2O}\\\\m_{H_2O}=74.8gH_2O

Regards!

6 0
3 years ago
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