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Sergio [31]
2 years ago
6

At what position in its elliptical orbit is the speed of a planet a maximum? when it is closest to the sun when it is farthest f

rom the sun when it is midway between its farthest and closest distances to the sun everywhere in its orbit, the speed is constant (b) At what position is the speed a minimum? when it is closest to the sun when it is farthest from the sun when it is midway between its farthest and closest distances to the sun everywhere in its orbit, the speed is constant
Physics
1 answer:
Phantasy [73]2 years ago
7 0

Answer:

1.when it is closest to the sun

2.when it is midway between its farthest

Explanation:

According to the law of  Kepler's

T ² ∝ r³

T=Time period

r=semi major axis

We also know that time period T given as

T=\dfrac{2\pi r}{v}

v=Speed

v=\dfrac{2\pi r}{T}

v\alpha \dfrac{r}{T}

v\alpha \dfrac{r}{T}

v^2\alpha \dfrac{r^2}{T^2}

v^2\alpha \dfrac{r^2}{r^3}

v^2\alpha \dfrac{1}{r}

v\alpha \dfrac{1}{\sqrt{r}}

So we can say that ,when r is more then the speed will be minimum and when r is low then speed will be maximum.

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nata0808 [166]

Answer:

The magnetic field strength is 0.29 T.

Explanation:

Given that,

Length of current-carrying wire, L = 52 cm = 0.52 m

Current, I = 15 A

Magnetic force, F = 2.3 N

We need to find the magnetic field strength. We know that the magnetic force is given by :

F=ILB

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B=\dfrac{F}{IL}\\\\B=\dfrac{2.3}{0.52\times 15}\\\\B=0.29\ T

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3 years ago
What is Archimedes principle?​
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2 years ago
A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.
ikadub [295]

Answer:

b) No acceleration in the vertical

c) 35N

d) 35N

e) 8.75\ m/sec^2

Explanation:

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b) The vertical movement is restrained by the normal force which opposes to the weight. In absence of any other force, they both are in equilibrium and the net force is zero

c) The net horizontal force acting on the book is the vectorial sum of the applied force and the friction force. Since they lie in the same axis and are opposed to each other:

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d) The net force acting on the book is the vector sum of all forces in all axes. The normal and the weight cancel each other in the y-axis, so our resulting force is the x-axis net force, computed as above:

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