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Sergio [31]
2 years ago
6

At what position in its elliptical orbit is the speed of a planet a maximum? when it is closest to the sun when it is farthest f

rom the sun when it is midway between its farthest and closest distances to the sun everywhere in its orbit, the speed is constant (b) At what position is the speed a minimum? when it is closest to the sun when it is farthest from the sun when it is midway between its farthest and closest distances to the sun everywhere in its orbit, the speed is constant
Physics
1 answer:
Phantasy [73]2 years ago
7 0

Answer:

1.when it is closest to the sun

2.when it is midway between its farthest

Explanation:

According to the law of  Kepler's

T ² ∝ r³

T=Time period

r=semi major axis

We also know that time period T given as

T=\dfrac{2\pi r}{v}

v=Speed

v=\dfrac{2\pi r}{T}

v\alpha \dfrac{r}{T}

v\alpha \dfrac{r}{T}

v^2\alpha \dfrac{r^2}{T^2}

v^2\alpha \dfrac{r^2}{r^3}

v^2\alpha \dfrac{1}{r}

v\alpha \dfrac{1}{\sqrt{r}}

So we can say that ,when r is more then the speed will be minimum and when r is low then speed will be maximum.

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Answer:

C) is zero

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According to the law of energy conservation, the total mechanical energy of the object is conserved. A book falling a distance d would have a change in potential energy, resulting in the same change in kinetic energy. But the total mechanical energy must be the same. So there's 0 change in total energy of the system.

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The axis of the earth is<br> Tilted about 23.5 degrees<br> Vertical<br> Vertical
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Answer:

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Explanation:

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2 years ago
If we put negative charge between two similar positive charges then what is it's equilibrium? And how?​
Gnesinka [82]

Your question has been heard loud and clear.

Well it depends on the magnitude of charges. Generally , when both positive charges have the same magnitude , their equilibrium point is towards the centre joining the two charges. But if magnitude of one positive charge is higher than the other , then the equilibrium point will be towards the charge having lesser magnitude.

Now , a negative charge is placed in between the two positive charges. So , if both positive charges have same magnitude , they both pull the negative charge towards each other with an equal force. Thus the equilibrium point will be where the negative charge is placed because , both forces are equal , and opposite , so they cancel out each other at the point where the negative charge is placed. However if they are of different magnitudes , then the equilibrium point will be shifted towards the positive charge having less magnitude.

Thank you

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3 years ago
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Mechanical advantage of a machine is the ratio of the output force over the input force or M=Fo/Fi. Since M=1, Fi=Fo, or the input force is equal to the output force. This means that to raise the refrigerator that weighs 900 N, we need the same input force of 900 N, or Fo=Fi=900 N. 
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Range of a projectile motion is given by
R = v cos θ / g (v sin θ + sqrt(v^2 sin^2 θ + 2gy_0)); where R = 188m, θ = 41°, g = 9.8m/s^2, y_0 = 0.9

188 = v cos 41° / 9.8 (v sin 41° + sqrt(v^2 sin^2 41° + 2 x 9.8 x 0.9)) = 0.07701(0.6561v + sqrt(0.4304 v^2 + 17.64)) = 0.05053v + 0.07701sqrt(0.4304v^2 + 17.64)
0.07701sqrt(0.4304v^2 + 17.64) = 188 - 0.05053v
0.005931(0.4304v^2 + 17.64) = 35344 - 19v + 0.002553v^2
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19v = 35344 - 0.1046 = 35343.8954
v = 35343.8954/19 = 1860 m/s
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