Question

2 co (g) + C (g) -> C3O2 (g)

Answer 1

Answer:

b) 63.7 kJ

Explanation:

     $2 CO_{(g)} + C _{(s)} ----> C_{3}O_{2}$

we have ΔH = 127.3 kJ/mol  

for 1.00 mole of CO the equation can be re-written as,

$CO_{(g)} +\frac{1}{2} C _{(s)} ---->\frac{1}{2} C_{3}O_{2}$

since the number of moles are halved  ΔH also gets halved as per Hesse's law of constant summation,

ΔH =   $\frac{127.3}{2}$  

      =  63.7 kJ