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sasho [114]
3 years ago
10

Un tren parte de la ciudad A, a las 8 h. con una velocidad de 50 km/h, para llegar a la ciudad B a las 10 h. Allí permanece dura

nte media hora y reanuda la marcha a 80 km/h hasta que llega a la ciudad C una hora más tarde. Calcula la distancia que hay entre las distintas ciudades y la hora de llegada
Physics
1 answer:
amm18123 years ago
8 0

Answer:

AB = 100 km; BC = 80 km; AC = 180 km

Arrival time = 11:30

Explanation:

1. Distance from A to B

(a) Travel time

Time = 10:00 - 8:00 = 2.00 h

(b) Distance

Distance = speed × time = 50 km/h × 2.00 h = 100 km

2. Distance from B to C

Distance = 80 km/h × 1 h = 80 km

3. Distances

AB = 100 km

BC =    80 km

AC =  180 km

4. Arrival time

Start from A       = 08:00

Travel time to B =   2:00

Arrive at B          =  10:00

Wait time at B    =    0:30

Start from B        =  10:30

Travel time to C  =   1:00

Arrive at C            = 11:30

 

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<u>Answer:</u>

<em>Equivalence point and end point are terminologies in pH titrations and they are not the same. </em>

<u>Explanation:</u>

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<em>A pH less than 7 will be the result if the resultant is acidic and if it is basic the pH will be greater than 7. </em>In a strong base-strong acid and weak base-weak acid titration the pH at the equivalence point will be 7 indicating <em>neutral nature of the solution. </em>

3 0
3 years ago
A kangaroo jumps straight up to a vertical height of 1.45 m. How long was it in the air before returning to Earth?
dexar [7]

Answer:

1.08 s

Explanation:

From the question given above, the following data were obtained:

Height (h) reached = 1.45 m

Time of flight (T) =?

Next, we shall determine the time taken for the kangaroo to return from the height of 1.45 m. This can be obtained as follow:

Height (h) = 1.45 m

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Time (t) =?

h = ½gt²

1.45 = ½ × 9.8 × t²

1.45 = 4.9 × t²

Divide both side by 4.9

t² = 1.45/4.9

Take the square root of both side

t = √(1.45/4.9)

t = 0.54 s

Note: the time taken to fall from the height(1.45m) is the same as the time taken for the kangaroo to get to the height(1.45 m).

Finally, we shall determine the total time spent by the kangaroo before returning to the earth. This can be obtained as follow:

Time (t) taken to reach the height = 0.54 s

Time of flight (T) =?

T = 2t

T = 2 × 0.54

T = 1.08 s

Therefore, it will take the kangaroo 1.08 s to return to the earth.

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