Explanation:
The protons determines the atomic number which helps in identifying an atom of an element
We are given the data for the angle of incidence and angle of refraction.
The first part of the problem is to plot the deviation and the angle of incidence. The minimum deviation is 37 with 65 degrees as the corresponding angle of incidence. The maximum deviation is 69 with a corresponding angle of incidence of 30 degrees. It is not advisable to use small values for the angle of incidence since it would result to a higher deviation from Snell's Law.
Answer:
Decrease occur in kinetic energy.
Explanation:
The kinetic energy decreases when the the Bob swings reaches to the maximum height because the motion of the bob slower down. At maximum height, the kinetic energy decreases whereas the value of potential energy is the highest. The main reason of higher potential energy is that it depends on height of an object while on the other hand, kinetic energy depends on the motion of an object so that's why the value of kinetic energy decreases and potential energy increases at maximum height of the bob.
Final velocity = Vf=0 <span>
Initial velocity = Vi = 9.5m/s
Acceleration = a = -4.6m/s</span>²<span>
Time = t =? </span>
Now use the formula;<span>
Vf=Vi+at
<span>0=9.5 - 4.6m/s</span></span>²t
<span>
-9.5 = -4.6m/s</span>²(t)
9.5/4.6 = t<span>
<span>T= 2.01s</span></span>
Answer:
a.![F=7.83\times 10^{-51} N](https://tex.z-dn.net/?f=F%3D7.83%5Ctimes%2010%5E%7B-51%7D%20N)
b.Attractive
Explanation:
We are given that
![F=\frac{GM_1M_2}{R^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7BGM_1M_2%7D%7BR%5E2%7D)
![G=6.67\times 10^{-11} Nm^2/kg^2](https://tex.z-dn.net/?f=G%3D6.67%5Ctimes%2010%5E%7B-11%7D%20Nm%5E2%2Fkg%5E2)
Mass of an electron,![M_1=9.11\times 10^{-31} kg](https://tex.z-dn.net/?f=M_1%3D9.11%5Ctimes%2010%5E%7B-31%7D%20kg)
Mass of proton,![M_2=1836\times 9.11\times 10^{-31} kg](https://tex.z-dn.net/?f=M_2%3D1836%5Ctimes%209.11%5Ctimes%2010%5E%7B-31%7D%20kg)
Distance between electron and proton,R=![3.602nm=3.602\times 10^{-9} m](https://tex.z-dn.net/?f=3.602nm%3D3.602%5Ctimes%2010%5E%7B-9%7D%20m)
![1nm=10^{-9} m](https://tex.z-dn.net/?f=1nm%3D10%5E%7B-9%7D%20m)
a.Substitute the values then we get
![F=\frac{6.67\times 10^{-11}\times 9.11\times 10^{-31}\times 1836\times 9.11\times 10^{-31}}{(3.602\times 10^{-9})^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%209.11%5Ctimes%2010%5E%7B-31%7D%5Ctimes%201836%5Ctimes%209.11%5Ctimes%2010%5E%7B-31%7D%7D%7B%283.602%5Ctimes%2010%5E%7B-9%7D%29%5E2%7D)
![F=7.83\times 10^{-51} N](https://tex.z-dn.net/?f=F%3D7.83%5Ctimes%2010%5E%7B-51%7D%20N)
b.We know that like charges repel to each other and unlike charges attract to each other.
Proton and electron are unlike charges therefore, the force between proton and electron is attractive.