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Andru [333]
3 years ago
5

The ph of a 0.15 m aqueous solution of naz (the sodium salt of hz) is 10.7. what is the ka for hz?

Chemistry
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:  
NaZ + H2O <----> HZ + OH- 
 [OH-] = [HZ] 
 [NaZ] = 0.15 M 
 pH = 10.7, so the pOH = 14-10.7 = 3.3; [OH-] = 10^-3.3 = 5.01E-4 
 kb = [OH-][HZ]/[NaZ] = (5.01E-4)^2/0.15 = 1.67E-6 
 ka = kw/kb = 1E-14/1.67E-6 = 5.99E-9 = 6.0E-9
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Iron (III) oxide is formed when Iron combines with oxygen in the air. How many grams of Fe₂O₃ are formed when 16.7 grams of reac
sladkih [1.3K]

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23.9g of Fe₂O₃ are produced

Explanation:

<em>Are formed when 16.7g of Fe reacts completely...</em>

<em />

Based on the reaction:

4Fe + O₃ → 2Fe₂O₃

<em>4 moles of Iron react per 1 mole of O₃ producing 2 moles of Fe₂O₃.</em>

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To solve this question we need to convert the mass of iron to moles. The ratio of reaction is 2:1 -That is, 2 moles of Fe produce 1 mole of Fe₂O₃-. Thus, we can find the moles of Fe₂O₃ produced and its mass:

<em>Moles Fe -Molar mass: 55.845g/mol-:</em>

16.7g Fe * (1mol / 55.845g) = 0.299 moles of Fe

<em>Moles Fe₂O₃:</em>

0.299 moles Fe * (2 mol Fe₂O₃ / 4 mol Fe) = 0.150 moles Fe₂O₃

<em>Mass Fe₂O₃ -Molar mass 159.69g/mol-:</em>

0.150 moles Fe₂O₃ * (159.69g / mol) =

<h3>23.9g of Fe₂O₃ are produced</h3>

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What is the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis according to the balanced equation:
Zinaida [17]

Taking into account the reaction stoichiometry, the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis is 25.956 grams.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 H₂O → 2 H₂ + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • H₂O: 2 moles
  • H₂: 2 moles
  • O₂: 1 mole

The molar mass of the compounds is:

  • H₂O: 18 g/mole
  • H₂: 2 g/mole
  • O₂: 32 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • H₂O: 2 moles ×18 g/mole= 36 grams
  • H₂: 2 moles ×2 g/mole= 4 grams
  • O₂: 1 mole ×32 g/mole= 32 grams

<h3>Definition of theorical yield</h3>

The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Theorical yield of O₂</h3>

The following rule of three can be applied: if by reaction stoichiometry 36 grams of water form 32 grams of oxygen, 29.2 grams of water form how much mass of oxygen?

mass of oxygen=\frac{29.2 grams of waterx32 grams of oxygen}{36 grams of water}

<u><em>mass of oxygen= 25.956 grams</em></u>

Finally, the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis is 25.956 grams.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

6 0
1 year ago
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