What is atomic radius? Does it decrease going up or down a group?

____ can be found in many forms including in the chemicals found in food

Rzqust [24]

A. Chemical energy can be in many forms including in the chemicals found in food

4 0

3 years ago

Bromine, a liquid at room temperature has a boiling point of 58 degrees celsius and a melting point at -7.2 degree celsius bromi

ra1l [238]

Hello!

Bromine can be classified as a pure substance.

Why?

Bromine is an element with atomic number 35 on group 17 of the Periodic Table. That's the first sign that shows us that it is a pure substance.

But the fact that it has a clear and defined boiling and melting point is a sign that we are in the presence of a pure substance. Pure substances are characterized by defined boiling and melting points.

Mixtures usually have a range of temperatures in which they melt and boil.

Have a nice day!

8 0

4 years ago

Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2N

Vitek1552 [10]

Answer : The value of work done for the system is 1144.69 J

Explanation :

First we have to calculate the moles of $NaN_3$

$\text{Moles of }NaN_3=\frac{\text{Mass of }NaN_3}{\text{Molar mass of }NaN_3}$

Molar mass of $NaN_3$ = 65.01 g/mole

$\text{Moles of }NaN_3=\frac{20.2g}{65.01g/mole}=0.311mole$

Now we have to calculate the moles of nitrogen gas.

The balanced chemical reaction is,

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced reaction we conclude that

As, 2 mole of $NaN_3$ react to give 3 mole of $N_2$

So, 0.311 moles of $NaN_3$ react to give $\frac{0.311}{2}\times 3=0.466$ moles of $N_2$

Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of $N_2$ gas = 1.00 atm

V = Volume of $N_2$ gas = ?

n = number of moles $N_2$ = 0.466 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $22^oC=273+22=295K$

Putting values in above equation, we get:

$1.00atm\times V=0.466mole\times (0.0821L.atm/mol.K)\times 295K$

$V=11.3L$

As initially no nitrogen was present. So,

Volume expanded = Volume of nitrogen evolved

Thus,

Expansion work = Pressure × Volume

Expansion work = 1.00 atm × 11.3 L

Expansion work = 11.3 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 11.3 × 101.3 = 1144.69 J

Therefore, the value of work done for the system is 1144.69 J

5 0

3 years ago

Why is haemoglobin a pure substance

dem82 [27]

<span>Haemoglobin is a pure substance because it contains only one type of atom. </span>

6 0

3 years ago

How many molecules are present in 265 moles of CCl

Solnce55 [7]

Answer:

Option C. 1.60x10^26 molecules

Explanation:

Avogadro's hypothesis proved that that 1 mole of any substance contains 6.02x10^23 molecules.

From the above, we understood that 1 mole of CCl4 contains 6.02x10^23 molecules.

If 1 mole of CCl4 contains 6.02x10^23 molecules,

then, 265 moles of CCl4 will contain = 265 x 6.02x10^23 = 1.60x10^26 molecules

From the calculation made above, 265 moles of CCl4 contains 1.60x10^26 molecules.

5 0

3 years ago