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2 years ago

7

What is the classification of the reaction shown in the equation below?

1 answer:

ad-work [718]2 years ago

6 0

Answer:

d

Explanation:

because is a reducing agent, O 2 is an oxidizing agent.

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Se lanza verticalmente una esfera con una rapidez de 30m/se. Determinar la rapidez de la esfera a una altura de 40m (g=10m/s2)

sergeinik [125]

$v^2-{v_0}^2=2a(x-x_0)$

dónde $v$ es la velocidad de la esfera, $v_0$ es suya velocidad inicial, $a=-g$ la aceleración debida a la gravedad, $x$ la posición, y $x_0$ la posición inicial. Tomamos $x_0=0\,\mathrm m$ a referirse a la posición de la esfera en el momento que la esfera fue lanzada.

Entonces

$v^2-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-10\,\dfrac{\mathrm m}{\mathrm s^2}\right)(40\,\mathrm m)$

$\implies v^2=100\,\dfrac{\mathrm m^2}{\mathrm s^2}\implies v=\pm10\,\dfrac{\mathrm m}{\mathrm s}$

Esto nos dice que la esfera alcanza una altura de 40 m en dos momentos - una vez hacia arriba y una vez hacia abajo. Sin embargo, independientemente del signo de la velocidad, sabemos que suya magnitud es 10 m/s, y así tenemos una rapidez de 10 m/s también en ambos momentos.

4 0

3 years ago

A ray of light traveling through air strikes a piece of diamond at an angle of incidence equal to 56 degrees. Calculate the angu

Montano1993 [528]

Answer:

The angle of separation is $\Delta \theta = 0.93 ^o$

Explanation:

From the question we are told that

The angle of incidence is $\theta _ i = 56^o$

The refractive index of violet light in diamond is $n_v = 2.46$

The refractive index of red light in diamond is $n_r = 2.41$

The wavelength of violet light is $\lambda _v = 400nm = 400*10^{-9}m$

The wavelength of red light is $\lambda _r = 700nm = 700*10^{-9}m$

Snell's Law can be represented mathematically as

$\frac{sin \theta_i}{sin \theta_r} = n$

Where $\theta_r$ is the angle of refraction

=> $sin \theta_r = \frac{sin \theta_i}{n}$

Now considering violet light

$sin \theta_r__{v}} = \frac{sin \theta_i}{n_v}$

substituting values

$sin \theta_r__{v}} = \frac{sin (56)}{2.46}$

$sin \theta_r__{v}} = 0.337$

$\theta_r__{v}} = sin ^{-1} (0.337)$

$\theta_r__{v}} = 19.69^o$

Now considering red light

$sin \theta_r__{R}} = \frac{sin \theta_i}{n_r}$

substituting values

$sin \theta_r__{R}} = \frac{sin (56)}{2.41}$

$sin \theta_r__{R}} = 0.344$

$\theta_r__{R}} = sin ^{-1} (0.344)$

$\theta_r__{R}} = 20.12^o$

The angle of separation between the red light and the violet light is mathematically evaluated as

$\Delta \theta = \theta_r__{R}} - \theta_r__{V}}$

substituting values

$\Delta \theta =20.12 - 19.69$

$\Delta \theta = 0.93 ^o$

6 0

3 years ago

The magnetic field 0.0 2M from a wire is 0.1 T. What is the magnitude of the magnetic field of 0.0 1M from the same wire?

Anika [276]

Answer:

Explanation:

Question

5 0

2 years ago

What is the inverse of f ( x ) ? <br><br>f ( x ) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7Bx%20-%206%7D" id="TexFormu

vladimir1956 [14]

The inverse of f(x) is (6x + 2)/x.

<h3>What is an inverse function?</h3>

The inverse function is defined as a function obtained by reversing the given function.

Given that f(x) = 2/(x-6)

To determine the inverse of a function, all you have to do is switch where x and y are and resolve for y.

So after switching x and y,

f(x) = y = 2/(x-6)

becomes

x = 2/(y - 6)

Now, we solve for y regularly.

f(x) = y = 2/(x-6)

Solve for y :

⇒ x(y - 6) =2

⇒ xy - 6x = 2

⇒ y = (6x + 2)/x

Therefore the inverse of f(x) is (6x + 2)/x

Learn more about inverse function here:

brainly.com/question/2541698

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5 0

1 year ago

If you could travel with speed of light (3.0e5 km/s) it would take only 2.5 minutes to reach venus. how far is venus from earth

motikmotik

D=S/T ,S=3.0e5km/s × 2.5min×60
D=4.5×e6km

7 0

3 years ago