This problem is providing us with the volume of toluene, 0.16 m³, and the local ventilation rate 28.34 m³/min, that is inside a drum at 30 °C and 1 atm. Thus, the time to evaporate all of the toluene is required as well as the parts per million in the drum, and found to be 96.2 min and 3.77 ppm respectively.
<h3>Ventilation:</h3>In mass transfer problems, ventilation involves mass transfer coefficients, cross-section area and saturation pressure, that we can calculate for this problem as shown below:
After that, we can calculate the rate at which the toluene is evaporated:
Where all mol, m, atm, L and atm are cancelled out. Next, given the volume of toluene and its density at 30 °C, 0.8574 g/mL, one can calculate its mass and hence the time to evaporate it all:
Next, the concentration of toluene in parts per million can be calculated with the rate at which toluene is evaporated and the local ventilation rate via the following equation:
Learn more about mass transfer: brainly.com/question/25309236