State the physical property that makes it possible to separate a solution by distillation

which of these species is most likely to be a lewis acid and is also least likely to be a bronsted acid

pochemuha

Answer:

This question is incomplete but the completed question is below

Which Of These Species Is Most Likely To Be A Lewis Acid And Is Also Least Likely To Be A Brønsted Acid? (A) NH4⁺ (B) BF₃ (C) H₂O (D) OH⁻

The correct option is B

Explanation:

A lewis acid is a substance that accepts (or is capable of accepting) a pair of electrons. For example BF₃, while a lewis base is a substance that donates (or is capable of donating) a pair of electrons. For example OH⁻.

If we take a look at the boron (B) in BF₃, it has 3 electrons on it's outermost shell, each of which are bonded to flourine and can still accept a pair of electrons (lone pair). This makes it very likely to be a lewis acid.

Bronsted lowry acid is a substance that donates or can donate a proton or H⁺ (for example HCl) while bronsted lowry base is a substance that accepts or can accept a proton or H⁺ (for example NH₃).

BF₃ cannot donate a proton or H⁺ hence it is least likely to be called a bronsted acid.

6 0

3 years ago

What is the mole fraction of each component if 3.9 g of benzene (C6H6) is dissolved in 4.6 g of toluene (C7H8)

Savatey [412]

Answer:

Step 1 of 6

(a)

The mass of benzene is , so calculate the moles of benzene as follows:

The mass of toluene is, so calculate the moles of toluene as follows:

Now, calculate the mole fraction as follows:

Therefore, the mole fraction of benzene and toluene is and respectively.

Step 2 of 6

(b)

The formula to calculate the partial pressure is as follows:

Here, is the partial pressure of benzene, is the vapour pressure of pure benzene and is the mole fraction of benzene.

Vapour pressure of pure benzene at is.

Substitute the values in the equation as follows:

Therefore, the partial pressure is .

Step 3 of 6

(c)

Vapor pressure of the solution at 1 atm is .

When the total pressure of the vapour pressure of the mixture is at a temperature, then, the solution boils. It corresponds to the boiling point of the solution.

Calculate the total pressure of the solution at as follows:

Since, the total pressure is less than the atmospheric pressure, the solution will not boil at .

Calculate the total pressure of the solution at as follows:

Since, the total pressure is greater than the atmospheric pressure, the solution will boil at .

Therefore, the boiling point of the solution is .

Step 4 of 6

(d)

Mole fraction of benzene at is calculated as follows:

Mole fraction of toluene at is calculated as follows:

Therefore, the mole fractions of benzene and toluene are and respectively.

Step 5 of 6

(e)

Vapor pressure of benzene at is .

Partial pressure of benzene is calculated as follows:

Vapor pressure of toluene at is .

Partial pressure of toluene is calculated as follows:

Step 6 of 6

Weight composition of the vapour that is in equilibrium with the solution is calculated as follows:

Explanation:

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4 0

3 years ago

Read 2 more answers

I need help with these questions, please!

lbvjy [14]

Answer:

1. Ionic bond

2. High melting point and high boiling point for ionic bonds while covalent bonds have low melting and boiling point.

3. The similarity is that ionic and covalent bonding lead to the creation of stable molecules.

4. 4Fe + 3O2 → 2Fe2O3

5. It uses the process of fission.

6. Fission involves the splitting of radioactive elements into smaller particles/compounds while Fusion involves combining of two or more atomic nuclei to form one or more different atomic nuclei and subatomic particles.

7. Nuclear power plants produce little to no greenhouse gas.

Nuclear power plants produce a large amount of energy for a small mass of fuel.

Nuclear is less expensive.

6 0

4 years ago

How many moles of sodium hydroxide would react with 1 Mole of sulphuric acid?

Paul [167]

Answer:

Two moles.

Explanation:

Sulphuric (sulfuric) acid $\rm H_2SO_4$ is a diprotic acid. When one mole of $\rm H_2SO_4$ molecules dissolve in water, two moles of $\rm H^{+}$ ions would be produced.

$\rm H_2SO_4 \to 2\, H^{+} + {SO_4}^{2-}$ .

On the other hand, sodium hydroxide $\rm NaOH$ is a monoprotic base. When one mole of $\rm NaOH$ formula units dissolve in water, only one mole of hydroxide ions $\rm OH^{-}$ would be produced.

$\rm NaOH \to Na^{+} + OH^{-}$ .

Note that $\rm H^{+}$ and $\rm OH^{-}$ react at a one-to-one ratio:

$\rm H^{+} + OH^{-} \to H_2O$ .

As a result, it would take $2\; \rm mol$ of $\rm OH^{-}$ to react with the $\rm 2\; mol$ of $\rm H^{+}$ that was released when $1\; \rm mol$ of $\rm H_2SO_4$ is dissolved in water. Since one mole of $\rm NaOH$ formula units could produce only one mole of $\rm OH^{-}$ , it would take $\rm 2\; mol$ of $\rm NaOH$ formula units to produce that $2\; \rm mol$ of $\rm OH^{-}$ for reacting with $1\; \rm mol$ of $\rm H_2SO_4$ .