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3 years ago

Which one of the following si units is used to measure current?

1 answer:

6 0

The unit of electric current is the 'ampere'.

That's the current in the circuit when one coulomb of charge
flows past any fixed point every second.

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The change in momentum of an object is equal to the Question 4 options: Force acting on it times its velocity. impulse acting on

lesya [120]

Answer:

impulse acting on it

Explanation:

The impulse is defined as the product between the force applied to an object (F) and the time interval during which the force is applied ( $\Delta t$ ):

$I=F\Delta t$

We can prove that this is equal to the change in momentum of the object. In fact, change in momentum is given by:

$\Delta p = m \Delta v$

where m is the mass and $\Delta v$ is the change in velocity. Multiplying and dividing by $\Delta t$ , we get

$\Delta p = m \frac{\Delta v}{\Delta t} \Delta t$

and since $\frac{\Delta v}{\Delta t}$ is equal to the acceleration, a, we have

$\Delta p = ma \Delta t$

And since the product (ma) is equal to the force, we have

$\Delta p = F \Delta t$

which corresponds to the impulse.

5 0

3 years ago

Astronaut John's mass is 75 kg. He is floating at rest in the space station holding a 5.0 kg pillow. When his friend Bill enters

Murljashka [212]

Answer:

my name is Deepika Pandey anion I am 9 years old my father name is Dinesh Pandey my name is and my sister name is sister name is a

4 0

2 years ago

What is the static friction force??

Paul [167]

55 Kg has a weight of 55x9.8= 539 N
That is equal to the Normal force.
The static friction = 0.19 x 539 = 102.4 N

6 0

3 years ago

Which of the following can be the first step to take in organizing data

Natalka [10]

the first step would be gathering information , and making sure its correct

5 0

3 years ago

An object moving in circular motion has a mass of 15 kg and a centripetal acceleration of 10 m/s2. What is the centripetal force

sweet-ann [11.9K]

Answer:

1) A

2) C

3) B

4) A

5) Incomplete information(picture missing)

6) Incomplete information(picture missing)

7) Incomplete information(picture missing)

8) A

9) C

10) C

Explanation:

1) m = 15kg, a = $10ms^{-2}$ , F = ma = 15*10 = 150N

2) m = 3kg, v = $4ms^{-1}$ , r = 4m, F = $\frac{mv^{2} }{r}$

$\frac{3*4^{2} }{4}$ = 12N

3) a = $10ms^{-2}$ , r = 10m, v=?

F = $\frac{mv^{2} }{r}$ and F = ma

equating the two equations and cancelling a, we have:

$\frac{v^{2} }{r}$ = a

making v the subject of formula, we have:

v = $\sqrt{ar}$

= $\sqrt{100}$

= 10 $ms^{-1}$

4) r = 10m, v = $5ms^{-1}$ , a = ?

F = $\frac{mv^{2} }{r}$

F = ma

equating the above equations and making a subject of formula, we get:

a = $\frac{v^{2} }{r}$

a = 25/10 = 2.5 $ms^{-2}$

5) I can't find the picture associated with this question

6) I can't find the picture associated with this question

7) I can't find the picture associated with this question

8) F = $\frac{mv^{2} }{r}$

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = $v^{2}$

Now, if v is tripled

F = $(3v)^{2}$

F = 9 $v^{2}$

We can see that the force will be 9X greater than it was.

9) F = $\frac{mv^{2} }{r}$

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = $v^{2}$

Now, if v is doubled

F = $(2v)^{2}$

F = 4 $v^{2}$

We can see that the force will be 4X greater than it was.

10) F = $\frac{mv^{2} }{r}$

assuming m and v is unity, that is the values are 1 respectively

F = 1/r

if r is doubled,

F = 1/2 * 1/r

We can see that the force is 1/2 as big as it was

7 0

3 years ago