How much heat is needed to vaporize 33.3 grams of ethyl alcohol at its boiling point of 78.0°C? The latent heat of vaporization
2 answers:
Answer:
Q = 28538.1 J
Explanation:
As we know that heat require to vaporize the ethyl alcohol is given as
Q = mL
here we know that
m = mass = 33.3 gram
L = latent heat of fusion = 857 J/g
now from above formula
so heat required in three significant figures is given as
so heat required to vaporize ethyl alcohol is
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