Answer:
The time of heating
Explanation:
Let us analyse the experiment closely; the temperature of the liquid increases as the time of heating increases. This implies that the temperature of the liquid is dependent on the time of heating of the liquid. The longer the time of heating, the greater the increase in temperature until the boiling temperature is eventually attained.
Hence, the temperature of the liquid is the dependent variable, the time of heating is the independent variable when the heating rate is held constant.
Reaction of Copper with Mercuric Nitrate is as follow,
Cu + Hg(NO₃)₂ → Cu(NO₃)₂ + Hg
According to equation,
1 Mole of Cu reacts to form = 1 Mole of Hg
So,
1.20 Moles of Cu will react to produce = X Moles of Hg
Solving for X,
X = (1.20 mol × 1 mol) ÷ 1 mol
X = 1.20 mol of Hg
Result:
1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.
Answer:
In physics, a fluid is a liquid, gas, or other material that continuously deforms (flows) under an applied shear stress, or external force.
Explanation:
They have zero shear modulus, or, in simpler terms, are substances which cannot resist any shear force applied to them.
Answer:- 448 mL of hydrogen gas are formed.
Solution:- It asks to calculate the volume of hydrogen gas formed in milliliters at STP when 0.020 moles of magnesium reacts with excess HCl acid. The balanced equation is:
There is 1:1 mol ratio between Mg and hydrogen gas. So, the moles of hydrogen gas is also equals to the moles of Mg reacted.
moles of Hydrogen gas formed = 0.020 mol
At STP, volume of 1 mol of the gas is 22.4 L. We need to calculate the volume of 0.02 moles of hydrogen gas.
= 0.448 L
They want answer in mL. So, let's convert L to mL using the conversion formula, 1L = 1000mL
= 448 mL
So, 0.020 moles of magnesium would produce 448 mL of hydrogen gas at STP on reacting with excess of HCl acid.
(a) 33.6 L of oxygen would be produced.
(b) 106 grams of would be needed
<h3>Stoichiometric calculations</h3>
1 mole of gas = 22.4 L
(a) From the equation, 2 moles of produce 3 moles of . 1 mole of will, therefore, produce 1.5 moles of .
1.5 moles of oxygen = 22.4 x 1.5 = 33.6 L
(b) 22.4 L of is produced at STP. This means that 1 mole of the gas is produced.
From the equation, 1 mole of requires 1 mole of .
Molar mass of = (23x2)+ (12)+(16x3) = 106 g/mol
Mass of 1 mole = 1 x 106 = 106 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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