Answer: 116.926 km/h
Explanation:
To solve this we need to analise the relation between the car and the Raindrops. The cars moves on the horizontal plane with a constant velocity.
Car's Velocity (Vc) = 38 km/h
The rain is falling perpedincular to the horizontal on the Y-axis. We dont know the velocity.
However, the rain's traces on the side windows makes an angle of 72.0° degrees. ∅ = 72°
There is a relation between this angle and the two velocities. If the car was on rest, we will see that the angle is equal to 90° because the rain is falling perpendicular. In the other end, a static object next to a moving car shows a horizontal trace, so we can use a trigonometric relation on this case.
The following equation can be use to relate the angle and the two vectors.
Tangent (∅) = Opposite (o) / adjacent (a)
Where the Opposite will be the Rain's Vector that define its velocity and the adjacent will be the Car's Velocity Vector.
Tan(72°) = Rain's Velocity / Car's Velocity
We can searching for the Rain's Velocity
Tan(72°) * Vc = Rain's Velocity
Rain's Velocity = 116.926 km/h
Answer:
Hey
The rope isn't moving because each boy is pulling with the same force on opposite ends. That being said the bot pulling force is balanced.
Inside the rope are molecules connecting the whole thing together. The force they exert on each other must be equal because they aren't moving but are still exerting forces
Answer:
0.001225 kg/L × 720 000 000 L = 882000 kg
Explanation:
Given:
The equation to solve is given as:
0.001225 kg/L × 720 000 000 L = ?
Let us write each term of the product in terms of power of 10.
As 0.001225 has 6 digits after the decimal place, therefore, we use the exponent 6 for 10 and the sign is negative. This gives,
Now, for 720000000 L there are 6 zeros after 720. So, we use exponent 6 but with a positive sign. This gives,
Now, finding the product, we get:
Therefore, the product is equal to:
0.001225 kg/L × 720 000 000 L = 882000 kg
Answer:
The number of free electrons per cubic meter is 
Explanation:
It is given that,
The number of free electrons per cubic meter is, 1.3
Electrical conductivity of metal, 
Density of metal, 
Atomic weight, A = 107.87 g/mol
Let n is the number of free electrons per cubic meter such that,
Where
is the density of silver atom
is the Avogadro number
A is the atomic weight of silver
or
Hence, this is the required solution.
