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Shalnov [3]
3 years ago
15

To prevent hydroplaning, _____. A. slow down B. speed up C. deflate your tires D. use cruise control

Engineering
1 answer:
Oksana_A [137]3 years ago
7 0

<u>Answer:</u>

<em><u>a. slow down</u></em>

<u>Explanation:</u>

To properly answer this question, you must understand what hydroplaning is. Hydroplaning is essentially when a car begins to slide on a wet road and the driver cannot control the vehicle. This happens because of an overflow in water on the road which causes the tires to begin to skim on the surface of the water. Having a proper amount of tire tread, typically 5/23 inches deep or above, will reduce chances of a car hydroplaning on a wet surface.

<em>* note:</em>

<em>if you would like a better understanding of what hydroplaning looks like, there are videos on the internet you could watch that show real life footage of what it looks like when cars hydroplane. I recommend searching up 'car hydroplaning.'</em>

<em />

Now that we fully understand the question, let's examine each option individually and determine what is the best thing to do to prevent hydroplaning.

<em><u>option a</u></em>

<em><u>slow down</u></em>

<em><u /></em>

When a persons car begins to hydroplane, it may be going so fast that it becomes difficult to control. Therefore, slowing down to reduce the speed of the car would be your best bet to try and regain control.

<u><em>option b</em></u>

<u><em>speed up</em></u>

<u><em /></u>

Stepping on the accelerator will increase the speed of the car which will cause it continue to skim on the surface of the water. This may cause the driver to lose even more control of the vehicle.

<u><em>option c</em></u>

<u><em>deflate your tires</em></u>

<u><em /></u>

Deflating your tires would not be a very reliable option, as it can make you lose control even more. It is also not a guarantee that you would even be able to deflate your tires.

<u><em>option d</em></u>

<u><em>use cruise control</em></u>

<u><em /></u>

If you put your car on cruise control it can punctually cause you to lose more control and cause your car to increase more speed.

Now that we have gone through each option individually, we can determine that option a 'slow down' is the best thing to do to prevent hydroplaning.

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Answer:

Composite panel garage doors

Explanation:

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Define Plastic vs elastic deformation.
Snowcat [4.5K]

Answer:

Plastic deformation, irreversible or permanent. Deformation mode in which the material does not return to its original shape after removing the applied load. This happens because, in plastic deformation, the material undergoes irreversible thermodynamic changes by acquiring greater elastic potential energy.

Elastic deformation, reversible or non-permanent. the body regains its original shape by removing the force that causes the deformation. In this type of deformation, the solid, by varying its tension state and increasing its internal energy in the form of elastic potential energy, only goes through reversible thermodynamic changes.

3 0
3 years ago
An AC generator supplies an rms voltage of 120 V at 50.0 Hz. It is connected in series with a 0.650 H inductor, a 4.80 μF capaci
Serggg [28]

Answer:

Explanation:

f = 50.0 Hz, L = 0.650 H, π = 3.14

C = 4.80 μF, R = 301 Ω resistor. V = 120volts

XL = wL = 2πfL

= 2×3.14×50* 0.650

= 204.1 Ohm

Xc= 1/wC

Xc = 1/2πfC

Xc = 1/2×3.14×50×4.80μF

= 1/0.0015072

= 663.48Ohms

1. Total impedance, Z = sqrt (R^2 + (Xc-XL)^2)= √ 301^2+ (663.48Ohms - 204.1 Ohm)^2

√ 90601 + (459.38)^2

√ 90601+211029.98

√ 301630.9844

= 549.209

Z = 549.21Ohms

2. I=V/Z = 120/ 549.21Ohms =0.218Ampere

3. P=V×I = 120* 0.218 = 26.16Watt

Note that

I rms = Vrms/Xc

= 120/663.48Ohms

= 0.18086A

4. I(max) = I(rms) × √2

= 0.18086A × 1.4142

= 0.2557

= 0.256A

5. V=I(max) * XL

= 0.256A ×204.1

=52.2496

= 52.250volts

6. V=I(max) × Xc

= 0.256A × 663.48Ohms

= 169.85volts

7. Xc=XL

1/2πfC = 2πfL

1/2πfC = 2πf× 0.650

1/2×3.14×f×4.80μF = 2×3.14×f×0.650

1/6.28×f×4.8×10^-6 = 4.082f

1/0.000030144× f = 4.082×f

1 = 0.000030144×f×4.082×f

1 = 0.000123f^2

f^2 = 1/0.000123048

f^2 = 8126.922

f =√8126.922

f = 90.14 Hz

8 0
3 years ago
2. When manipulating your pedals, you should use your
astra-53 [7]

Answer:

D. left foot for the accelerator and your right foot for the brake.

* Hopefully this helps:) mark me the brainliest:)!!

7 0
3 years ago
Read 2 more answers
1. A glass window of width W = 1 m and height H = 2 m is 5 mm thick and has a thermal conductivity of kg = 1.4 W/m*K. If the inn
emmasim [6.3K]

Answer:

1. \dot Q=19600\ W

2. \dot Q=120\ W

Explanation:

1.

Given:

  • height of the window pane, h=2\ m
  • width of the window pane, w=1\ m
  • thickness of the pane, t=5\ mm= 0.005\ m
  • thermal conductivity of the glass pane, k_g=1.4\ W.m^{-1}.K^{-1}
  • temperature of the inner surface, T_i=15^{\circ}C
  • temperature of the outer surface, T_o=-20^{\circ}C

<u>According to the Fourier's law the rate of heat transfer is given as:</u>

\dot Q=k_g.A.\frac{dT}{dx}

here:

A = area through which the heat transfer occurs = 2\times 1=2\ m^2

dT = temperature difference across the thickness of the surface = 35^{\circ}C

dx = t = thickness normal to the surface = 0.005\ m

\dot Q=1.4\times 2\times \frac{35}{0.005}

\dot Q=19600\ W

2.

  • air spacing between two glass panes, dx=0.01\ m
  • area of each glass pane, A=2\times 1=2\ m^2
  • thermal conductivity of air, k_a=0.024\ W.m^{-1}.K^{-1}
  • temperature difference between the surfaces, dT=25^{\circ}C

<u>Assuming layered transfer of heat through the air and the air between the glasses is always still:</u>

\dot Q=k_a.A.\frac{dT}{dx}

\dot Q=0.024\times 2\times \frac{25}{0.01}

\dot Q=120\ W

5 0
3 years ago
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