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natta225 [31]
3 years ago
9

What is a stack of membranes that packages chemicals

Physics
1 answer:
jeyben [28]3 years ago
5 0
That would be the Golgi Apparatus
You might be interested in
A solid, homogeneous sphere with a mass of m0, a radius of r0 and a density of rho0 is placed in a container of water. Initially
ivanzaharov [21]

Answer:

a) s,f,r  b) r c) f

Explanation:

To determine what happens with the sphere we use Newton's second law with the Archimedes principle that states that the thrust (B) on a body is equal to the weight of the liquid dislodged

For the sphere to be in equilibrium the sum of forces is zero

    B - W = 0

    B = W = mg

Now let's use the concept of density for the body and water

Solid sphere

   ρ = m / V

  V = 4/3 π r³

   m = ρ₀ (4/3 π r³)

   W = ρ₀ (4/3 π r³) g

Water  (a)

   ρ = mₐ / Vₐ

   mₐ = ρ Vₐ

   B = ρ Vₐ g

Let's replace and simplify

   ρ Vₐ g = ρ₀ (4/3 π r³) g

    ρ Vf = ρ₀ (4/3 π r³)            (1)

For the initial condition with rho, mo and ro the height of the water is H, let's analyze each case

a) We have the same mass, but less radius, as density is mass over volume density increases

   r  <ro        V <V₀   ⇒      ρ₁> ρ₀

When analyzing the equation (1) on the right side, this case is the most complicated because I can make the relationship between the density of the sphere and its volume change even when the mass is constant

Assume the three possibilities

- The product of (ρ₁ V) that does not matter in that case the left side does not change and the mark remains the same (s)

- The product (ρ₁ V) increases the left side must increase so the mark goes up (r)

- The product (ρ₁ V) decreases the left side should go down, so the low mark (f)

b) sphere the same radius, but the density increases.

In this case the right side of the equation (1) increases, therefore the left side must increase so that the volume must increase and consequently increase the height (r)

c) you have the same radius, but the mass decreases

      r = r₀     V = V₀     m <m₀        ρ₁ <ρ₀

The right side of the equation decreases, because the density decreases, the left side must decrease, for this the volume must decrease, lowering the height (f)

8 0
3 years ago
Which values are equivalent to the fraction below ? check all that apply. 2^4/2^7
Irina18 [472]
2^4/2^7 = 16/128 = 0.125
(1/2)^3= 0.125
1/8= 0.125
a and f are equivalent
5 0
3 years ago
Read 2 more answers
Simple curiosity is not a legitimate reason to complete a scientific investigation.
jok3333 [9.3K]
True......I would say...
7 0
3 years ago
Read 2 more answers
Como un astronauta utiliza la fuerza de hallar y empujar?
PilotLPTM [1.2K]

Answer:

La única manera en que nuestro astronauta sería capaz de empujar la nave espacial en el espacio sin alejarse sería usar algo llamado "unidad de propulsión de astronauta". Supongamos que el astronauta está usando un SPK soviético, el sistema de cohetes mochila más poderoso jamás utilizado en el espacio.

Explanation:

3 0
3 years ago
a mass of 4 kilograms is paced onto a spring snd it stretches 0.2 meters. Why is the spring constant?
Ray Of Light [21]

Answer:

fgch

Explanation:

5 0
3 years ago
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