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natta225 [31]
3 years ago
9

What is a stack of membranes that packages chemicals

Physics
1 answer:
jeyben [28]3 years ago
5 0
That would be the Golgi Apparatus
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Scientists are experimenting with a kind of gun that may eventually be used to fire payloads directly into orbit. In one test, t
kkurt [141]

Answer:

t=0.038s

Explanation:

Project mass m=3.8 kg

Initial speed vi= 0m/s

Final speed vf= 9.3×10³ m/s

Force F=9.3×10⁵N

To find

Time t

Solution

From Newtons second law we know that

∑F=ma

Where m is mass

a is acceleration

We can write this equation as

∑F=m(Δv/Δt)

=m\frac{v_{f}-v_{i}}{t}

Rearrange this equation to find time t

So

t=m\frac{v_{f}-v_{i}}{F}

Substitute the given values

t=3.8kg\frac{9.3*10^3m/s-0}{9.3*10^5N} \\t=0.038s  

5 0
3 years ago
Why is physics used to study stars?
goblinko [34]

Answer:

stars are made of matter

3 0
3 years ago
The property of water that contributes to its ability to stick to certain surfaces is called
Gekata [30.6K]

Answer: Adhesion

Explanation: Adhesion is the tendency of dissimilar particles or surfaces to cling to one another (cohesion refers to the tendency of similar or identical particles/surfaces to cling to one another). The forces that cause adhesion and cohesion can be divided into several types. This allows Particles in things like water to stick to surfaces

3 0
3 years ago
What is the value of work done on an object when a 50–newton force moves it 15 meters in the same direction as the force?
laila [671]

Answer:

Work done, W = 750 joules

Explanation:

It is given that,

Force acting on the object, F = 50 N

It moves to a distance of, d = 15 meters

We need to find the work done on an object. We know that the product of force and distance covered is called the work done. As the force and the displacement are in same direction. So,

W=F\times d

W=50\ N\times 15\ m

W = 750 joules

So, the work done on an object is 750 joules. Hence, this is the required solution.

4 0
3 years ago
A train can speed up at a uniform rate of 0.15 m/s2. In what minimum distance can
goblinko [34]

Answer:

d = 2083.33 m

Explanation:

Given that,

Acceleration of the train, a = 0.15 m/s²

The initial speed of the car, u = 0\

Final velocity, v = 25 m/s

We need to find the minimum distance covered by the train. Let it is d. Using third equation of kinematics as follows :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(25)^2-0}{2\times 0.15}\\\\d=2083.33\ m

So, the minimum distance is 2083.33 m

3 0
3 years ago
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