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3 years ago

Can somone pls help me??!! i’m very stuck

Physics

1 answer:

LenKa [72]3 years ago

7 0

Answer:

Explanation:

Her distance from home and Time increase

the stops when she gets to the library

then her distance from home decreases while her time increases

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Which water would you use to make salt dissolve the slowest?

harkovskaia [24]

Answer:

boiling water because salt dissolves quicker in hot Water and the hottest is boiling

4 0

3 years ago

While running, a person dissipates about 0.60 J of mechanical energy per step per kilogram of body mass. If a 61 kg person devel

liraira [26]

Answer:

2.66m/s

Explanation:

information we have

power: 65W

work per step per kilogram: 0.60J

mass: 61kg

length of a running step: 1.5m

---------------

the formula for power is:

$P=\frac{W}{t}$

where W is the work and t is time.

time is also defined as: $t=\frac{distance}{velocity}=\frac{d}{v}$

so substituting this into the formula for power we get:

$P=\frac{W*v}{d}$

where v is the velocity we are looking for, d is the distance per step: $d=1.5m$ , W is the work per step and P is power $P=65W$ .

we know that the work per step per kilogram is:

0.60J

so to find the work per step of his whole body we need to multiply the 0.60J by the 61 kilograms of his mas:

$W=0.60J*61kg\\W=36.6J$ this is the work per step of the person.

So now we can calculate the velocity using the formula for power

$P=\frac{W*v}{d}$

clearing for v:

$v=\frac{P*d}{W}\\$

and substituting known values:

$v=\frac{(65W)(1.5m)}{36.6J}= 2.66m/s$

6 0

3 years ago

Wts the average velocity

Alexeev081 [22]

Answer:

2.11 m/s

Explanation:

V=disp/time

V=(0.52m+3.7m)/(2)

V=4.22/2

V=2.11 m/s

5 0

3 years ago

Please help!! giving a lot of points

Readme [11.4K]

Question 1.

mass = 4500 kg
potential energy (p.e) = 67500 J

now, we know :

=》

$p.e = mgh$

=》

$67500 = 4500 \times 10 \times h$

=》

$67500 = 45000 \times h$

=》

$h = \dfrac{67500}{45000}$

=》

$h = 1.5 \: m$

note : if we take acceleration due to gravity as 9.8, then height = 1.53 m

Question 2.

mass = 4500 kg
kinetic energy = 63000 j

we know,

=》

$k.e = \dfrac{1}{2} mv {}^{2}$

=》

$63000 = \dfrac{1}{2} \times 4500 \times {v}^{2}$

=》

${v}^{2} = \dfrac{63000 \times 2}{4500}$

=》

${v}^{2} = 28$

=》

$v = \sqrt{28}$

=》

$v = 2 \sqrt{7} \: \: ms {}^{ - 1}$

=》

$5.29 \: \: ms {}^{ - 1}$

7 0

2 years ago

A +26.3 uC charge qy is repelled by a force

Musya8 [376]

Answer:

+1.46×10¯⁶ C

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C

Force (F) = 0.615 N

Distance apart (r) = 0.750 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Charge 2 (q₂) =?

The value of the second charge can be obtained as follow:

F = Kq₁q₂ / r²

0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²

0.615 = 236700 × q₂ / 0.5625

Cross multiply

236700 × q₂ = 0.615 × 0.5625

Divide both side by 236700

q₂ = (0.615 × 0.5625) / 236700

q₂ = +1.46×10¯⁶ C

NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C

5 0

2 years ago