What would be the volume in liters of an ideal gas, if a 0.425 mole sample of the gas had a temperature of 900 degrees celsius a
t a pressure of 3.00 atmospheres? (the ideal gas constant is 0.0821 l•atm/mol•k.)?
1 answer:
The ideal gas law relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a given ideal gas through the equation,
PV = nRT
If we are to determine the volume of the gas, we derive the equation such that it takes the form of,
V = nRT/P
Substituting,
V = (0.425 mol)(0.0821 L.atm/mol.K)(900 + 273 K) / 3 atm
V = 13.64 L
Thus, the volume of the ideal gas is approximately 13.64 L.
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C = m
------
V
50.0 mg/mL = mass
---------------
425 mL
mass = 50.0 * 425
mass => 21250 mg
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