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valentinak56 [21]
3 years ago
15

What would be the volume in liters of an ideal gas, if a 0.425 mole sample of the gas had a temperature of 900 degrees celsius a

t a pressure of 3.00 atmospheres? (the ideal gas constant is 0.0821 l•atm/mol•k.)?
Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0
The ideal gas law relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a given ideal gas through the equation,

                                 PV = nRT 

If we are to determine the volume of the gas, we derive the equation such that it takes the form of,
                                 V = nRT/P

Substituting,
             V = (0.425 mol)(0.0821 L.atm/mol.K)(900 + 273 K) / 3 atm

                            V = 13.64 L

Thus, the volume of the ideal gas is approximately 13.64 L. 
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The current scientific verdict on the phlogiston theory demonstrates which two of the following principles?
masha68 [24]

Answer:

The two valid principles are:

  • Scientific theories can be replaced by better theories.
  • An experiment can disprove a theory that scientists have accepted.

Explanation:

The scientific knwoledge is not inmutable; it may (and does) change with new discoveries.

In fact, scientific theories cannot be proved right, instead they are constantly tested to try to  disprove them. This is what the principle that theories are falsiable means.

As long as a scientific theory is not disproved it remains valid, but new discoveries may lead, eventually, to its disprovement.

Scientific knowledge evolves because new procedures, new technologies, and new evidence leads to a better understanding and better explanations.

5 0
3 years ago
Answer this plz I'm desperat
lord [1]
The problem the answer u are looking for a
8 0
3 years ago
Match each of the following topical dosage forms with its correct definition.
Dmitry [639]

Answer:

cream - contains a higher proportion of oil than water

ointment - dr4g mixed in approximately equal proportions of oil and water

i don't know about the other two sorry

8 0
2 years ago
HRISTINA HERRERA: Attempt 1
Lunna [17]

Answer:

7.5 g of hydrogen gas reacts with 50.0 g oxygen gas to form 57.5 g of water.

Explanation:

Here we have the check if the mass of the reactants is equal to the mass of the products.

Reactants

7.5+50=57.5\ \text{g}

Products

57.5\ \text{g}

The data is consistent with the law of conservation of matter.

Reactants

50+243=293\ \text{g}

Products

206+97=303\ \text{g}

The data is not consistent with the law of conservation of matter.

Reactant

17.7+34.7=52.4\ \text{g}

Products

62.4\ \text{g}

The data is not consistent with the law of conservation of matter.

Only the first data is consistent with the law of conservation of matter.

8 0
3 years ago
The standard enthalpy change for the following reaction is 873 kJ at 298 K.
Flura [38]

Answer:  - 436.5 kJ.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.

The given chemical reaction is,

2KCl(s)\rightarrow 2K(s)+Cl_2(g)  \Delta H_1=873kJ

Now we have to determine the value of \Delta H for the following reaction i.e,

K(s)+\frac{1}{2}Cl_2(g)\rightarrow KCl(s) \Delta H_2=?

According to the Hess’s law, if we divide the reaction by half then the \Delta H will also get halved and on reversing the reaction , the sign of enthlapy changes.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=\frac{1}{2}\times (-873kJ)

\Delta H_2=-436.5kJ

Hence, the value of \Delta H_2 for the reaction is -436.5 kJ.

8 0
3 years ago
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