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Yakvenalex [24]
4 years ago
13

Consider the reaction when aqueous solutions of potassium hydroxide and ammonium nitrate are combined. The net ionic equation fo

r this reaction is:
Chemistry
1 answer:
Reil [10]4 years ago
6 0

Answer: OH^-(aq)+NH_4^+(aq)\rightarrow NH_3(g)+H_2O(l)

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

KOH(aq)+NH_4NO_3(aq)\rightarrow KNO_3(aq)+NH_3(g)+H_2O(l)

The equation can be written in terms of ions as:

K^+(aq)+OH^-(aq)+NH_4^+(aq)+NO_3^-(aq)\rightarrow K^+(aq)+NO_3^-(aq)+NH_3(g)+H_2O(l)

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The ions which are present on both the sides of the equation are potassium and nitrate ions and hence are not involved in net ionic equation.

Hence, the net ionic equation is :

OH^-(aq)+NH_4^+(aq)\rightarrow NH_3(g)+H_2O(l)

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Calculate the volume 3.00 moles of a gas will occupy at 24.0˚C and 1.003 atm. *
vitfil [10]

Answer: 72.93 litres

Explanation:

Given that:

Volume of gas (V) = ?

Temperature (T) = 24.0°C

Convert 24.0°C to Kelvin by adding 273

(24.0°C + 273 = 297K)

Pressure (P) = 1.003 atm

Number of moles (n) = 3 moles

Molar gas constant (R) is a constant with a value of 0.0821 atm L K-1 mol-1

Then, apply ideal gas equation

pV = nRT

1.003 atm x V = 3.00 moles x 0.0821 atm L K-1 mol-1 x 297K

1.003 atm•V = 73.15 atm•L

Divide both sides by 1.003 atm

1.003 atm•V/1.003 atm = 73.15 atm•L/1.003 atm

V = 72.93 L

Thus, the volume of the gas is 72.93 litres

5 0
3 years ago
Find [cu2+] in a solution saturated with cu4(oh)6(so4) if [oh − ] is fixed at 2.3 ✕ 10−6 m. note that cu4(oh)6(so4) gives 1 mol
ki77a [65]
<span>

</span>Cu_4(OH)_6(SO_4)
<span>
You have OH-  conc = </span>2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is  4 : 6 = 2:3

So, for 2.3 ✕ 10−6 m OH-
[Cu2+] = \frac{2}{3} \times 2.3 \times 10^{-6}

= 1.53  \times 10^{-6} &#10;

6 0
4 years ago
An ideal gas has a volume of 14.5 L in a flexible balloon at 660.0 mmHg at
Alex787 [66]
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4 0
3 years ago
To make a 6.50M solution, how many moles of solute will be needed if 12.0 liters of solution are required
avanturin [10]

Answer:

78 moles of the solute

Explanation:

From the question;

  • Molarity of the solution is 6.50 M
  • Volume of the solution is 12.0 L

We want to determine the number of moles needed

We need to know that;

Molarity = Number of moles ÷ Volume

Therefore;

Number of moles = Molarity × Volume

Hence;

Number of moles = 6.50 M × 12.0 L

                             = 78 moles

Thus, the moles of the solute needed is 78 moles

8 0
3 years ago
Which of the following is a factor in natural selection?
Vera_Pavlovna [14]

Answer:

D.

Explanation:

Although all of these answers are similar, it seems that all three are the answer. I am sorry if the answer ends up being B but I'm pretty sure the answer is D. Charles Darwin's evolution theory "evolved", get it, from the natural selection theory. The theory is described as "the process whereby organisms better adapted to their environment tend to survive and produce more offspring." However, some factors that effect natural selection are competition, selection and variation. I believe all three fit the answer and therefore I believe answer D is correct.

5 0
3 years ago
Read 2 more answers
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