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inn [45]
3 years ago
12

When light hits the boundary between two different materials, it can undergo when light hits the boundary between two different

materials, it can undergo both reflection and refraction. refraction. reflection?
Physics
2 answers:
mash [69]3 years ago
6 0

Answer:

Explanation:

When light hits the boundary between two different materials, it can undergo both reflection and refraction.

Reflection is when light bounces off an object. If the surface is smooth and shiny, like glass, water or polished metal, the light will reflect at the same angle as it hit the surface. Light reflects from a smooth surface at the same angle as it hits the surface. The reflective property of material also depends on its density. E.g air and metal interface. The light may not be reflected much from air ( Less dense ), but it can reflect of a solid (more dense) due to the fact that they are less micro-scopic spaces in between molecules in a solid

Whereas, refraction owes to bending and change in direction of incident light as it passes through mediums with different densities. Less dense materials allow light to travel faster where as high dense materials slows the light down. The quantity of bend in light is given by snell's Law that involves the refractive indices of two material as function of speed of light traveling through the material

Rashid [163]3 years ago
3 0
When light hits the boundary between two different materials, it can undergo both reflection and refraction.

Reflection is the change in the direction of the wave that strikes the boundary between two materials.<span> It involves a change in the direction of waves when they clash with an obstacle.


Refraction  involves the change in the direction of waves as they move from one medium to  </span><span><span>another followed</span></span><span> by a change in speed and wavelength (this second medium should have different permitivity for the light to change its initial properties.)</span>




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How do atoms become more chemically stable?
Marat540 [252]

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3 0
3 years ago
A coffee filter of mass 1.2 grams dropped from a height of 1 m reaches the ground with a speed of 0.8 m/s. How much kinetic ener
iren [92.7K]

<u>Answer:</u> The energy gained by the air molecules is 0.011 J.

<u>Explanation:</u>

Law of conservation of energy states that energy can neither be created nor be destroyed but it can only be transformed from one form to another form.

Here, the potential energy of the coffee filter is getting converted into kinetic energy of the coffee filter and some energy is lost by it which is gained by the air molecules in the form of kinetic energy.

So, calculating the potential energy of coffee filter, we use the equation:

P = mgh

where,

m = mass of coffee filter = 1.2 g = 1.2\times 10^{-3}kg    (Conversion used: 1 kg = 1000 g)

g = acceleration due to gravity = 9.8m/s^2

h = height of coffee filter = 1 m

Putting values in above equation, we get:

P=1.2\times 10^{-3}kg\times 9.8m/s^2\times 1m\\\\P=1.176\times 10^{-2}J

  • Calculating the kinetic energy of coffee filter, we use the equation:

E=\frac{1}{2}mv^2

where,

m = mass of coffee filter = 1.2 g = 1.2\times 10^{-3}kg

v = speed of coffee filter = 0.8 m/s

Putting values in above equation, we get:

E=\frac{1}{2}\times 1.2\times 10^{-3}kg\times (0.8m/s)^2\\\\E=3.84\times 10^{-4}J

As, energy lost by coffee filter = energy gained by air molecules

So, energy lost by coffee filter = Potential energy - Kinetic energy

Energy lost by coffee filter = (1.176\times 10^{-2})-(3.84\times 10^{-4})=0.011J

Hence, the energy gained by the air molecules is 0.011 J.

5 0
3 years ago
A very hard rubber ball (m = 0.5 kg) is falling vertically at 4 m/s just before it bounces on the floor. The ball rebounds back
saw5 [17]

Answer:

The force exerted by the floor is 80 N.

Explanation:

Given that,

Mass of ball = 0.5 kg

Velocity= 4 m/s

Time t = 0.05 s

When the ball rebounds then the kinetic energy is

K.E =\dfrac{1}{2}mv^2

Where, m = mass of ball

v = velocity of ball

Put the value into the formula

K.E=\dfrac{1}{2}\times0.5\times(4)^2

K.E = 4\ J

The average force exerted by the floor on the ball = change in kinetic energy over collision time

F = \dfrac{4}{0.05}

F=80\ N

Hence, The force exerted by the floor is 80 N.

4 0
3 years ago
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