Answer:
a)48300 times
b)P = 821100 kg · m/s
Explanation:
Given that
m = 48300 kg
v= 23 m/s
We know that linear momentum (P) given as
P = m v
P = 48300 x 23 kg · m/s
So we can say that truck momentum is 48300 times its velocity.
Now given that
v= 17 m/s
P = m v
P = 48300 x 17 kg · m/s
P = 821100 kg · m/s
Answer:
The forces experienced by the middle particle are attractive, and the net force will remain the same (0) if and only if the distances of the sides particles to the middle particle are the same.
Explanation:
In example 20.3 the forces experienced by the middle particle are repulsive because all the particles are positive, for the case in which the particles on the sides are replaced for negative charge particles the forces experienced by the middle particle are attractive. Regarding the net force, because we don't know the distances we can not give a definitive answer, what we can say is that if the distances from the middle particle to the sides particles are the same the net force is zero for both cases (remain unchanged).
The correct option is B. More mass
Hope this helps you
Brainliest would be appreciated
-AaronWiseIsBae
Answer:
Explanation:
number of turns, N = 149
radius, r = 2.15 cm
Area, A = πr² = 3.14 x 2.15 x 2.15 x 10^-4 = 1.45 x 10^-3 m^2
Change in magnetic field, ΔB = 95.5 - 50.5 = 45 mT = 45 x 10^-3 T
time, Δt = 0.165 second
induced emf
e = N x dФ/dt
where, dФ be the change in flux.
e = N x A x ΔB/Δt
e = 149 x 1.45 x 10^-3 x 45 x 10^-3 / 0.165
e = 0.058 V
