<u>Distance traveled N/S:</u>
(80 m north) + (20 m south) + (60 m south)
(80 m) + (-20 m) + (-60 m)
<u><em>0 m north/south</em></u>
<u>Distance traveled E/W:</u>
(15 m east) + (35 m west)
(15 m) + (-35 m)
-20 m
<u><em>20 m west</em></u>
<u>Resultant distance:</u>
a² + b² = c²
a = 0 m north/south
b = 20 m west
c² = (0 m)² + (20 m)²
c² = (20 m)²
<u><em>c = 20 m</em></u>
<u><em>Overall displacement = 20 m</em></u>
Balanced chemical reaction: 2KClO₃ → 2KCl + 3O₂.
Potassium is metal from first group of Periodic table of elements, it has always oxidation number in compound +1.
Chlorine in the reactant state has oxidation number +5 (+1 + x + 3 · (-2) = 0) and it is reduced to -1 (+1 + x = 0) in <span>the product state.
</span>Oxygen in the reactant state has oxidation number -2 (+1 + 5 + 3 · x = 0) and it is oxidized to 0 (in molecule of oxygen) in the product state.
Answer:
ionic or covalent
Explanation:
The outermost electrons -- the valence electrons -- are able to interact with other atoms, and, depending on how those electrons interact with other the atoms, either an ionic or covalent bond is formed, and the atoms fuse together to form a molecule.
Answer:
CH3COOH
Explanation:
CH3COOH has the highest boiling point because it participates in the strongest intermolecular interactions. The -OH group can participate in hydrogen bonding with other -OH groups. Hydrogen bonds are very strong because they are the result of large partial positive charge on the hydrogen and large partial negative charge on the oxygen. When surrounded by other -OH groups, the partial positive charge on the hydrogen can form temporary bonds with the partial negative charge of an oxygen on another molecule. The stronger the intermolecular interactions, the more difficult they are to overcome, thus increasing the boiling point.
The strongest IMF the other molecules participate in are dipole-dipole. These interactions are not as strong as hydrogen bonding.
Answer:
See below
Explanation:
45 kJ / gm * .77 gm / liter * 13 liter = _________ kJ