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Alex_Xolod [135]
4 years ago
15

Some planetary scientists have suggested that the planet Mars has an electric field somewhat similar to that of the earth, produ

cing a net electric flux of 3.69×1016 N⋅m2/C into the planet's surface.Part A: Calculate the total electric charge on the planet. Part B: Calculate the magnitude of the electric field at the planet's surface (refer to the astronomical data inside the back cover).
Physics
1 answer:
Sergio039 [100]4 years ago
4 0

Answer:

Part a)

Q = 3.26 \times 10^5 C

Part b)

E = 255.45 N/C

Explanation:

Part a)

As we know that flux is defined as

\phi = \frac{Q}{\epsilon_0}

here we have

\phi = 3.69 \times 10^{16} N.m^2/C

now we have

3.69 \times 10^{16} = \frac{Q}{8.85 \times 10^{-12}}

Q = 3.26 \times 10^5 C

Part b)

Also we know that the radius of the planet is given as

R = 3.389\times 10^6 m

now the electric field is given as

E = \frac{kQ}{R^2}

here we have

E = \frac{(9\times 10^9)(3.26 \times 10^5)}{(3.389\times 10^6)^2}

E = 255.45 N/C

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