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3 years ago

7

A student pours Liquid A through filter paper. the liquid passes through the filter paper, but a residue remains on the filter.

Liquid A must have been a(n)
A - Element
B - Compound
C - Plasma
D - Mixture

2 answers:

AVprozaik [17]3 years ago

4 0

Answer:

I think it is A.Element maybe

Natasha2012 [34]3 years ago

3 0

Liquid a is D-mixture ! mixtures may contain insoluble substances like sand in watet

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What do scientist do to easily share measurement data they can understand

Jobisdone [24]

1. They use the same measuring system (metric)

2. Clearly and properly collect and record data, recording the procedure and results

3. Releasing the data into the public, letting everyone have access to it

maybe, I don't know what answer your teacher wants

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3 years ago

It is often necessary to prepare a dilute solution from a more concentrated solution rather than starting from a solid and just

valina [46]

Answer:

Take 10.0mL of your original solution and dilute it to 100.0mL and then, take 5.0mL of this solution and dilute it in another flask to 100.0mL

Explanation:

The initial solution of 0.3g of Red dye in 100mL has a concentration of:

0.3g Red dye × (1mol / 869g) = 3.4x10⁻⁴ mol Red Dye in 100mL = 0.100L:

3.4x10⁻⁴ mol / 0.1L = 3.4x10⁻³M

As you want a 1.7x10⁻⁵M solution, you need to dilute your solution:

3.4x10⁻³M / 1.7x10⁻⁵M = 200 times

Having this in mind, you must find the dilutions you must make to achieve the 200 of dilution factor (<em>Dilution factor is how many times you dilute a solution from a concetrated form).</em>

If you dilute the original solution taking 10.0mL to 100.0mL you dilute the solution: 100.0mL / 10.0mL = <em>10 times.</em>

Now, you need to dilute this solution another 20 times to achieve the 10*20 = 200 times of dilution.

If you take 5.0mL of the last solution and dilute it to 100.0mL you are diluting the solution 100.0mL / 5.0mL = <em>20 times.</em>

The dilution is:

3.4x10⁻³M × (10.0mL / 100.0mL) × (5.0mL / 100.0mL) = 1.7x10⁻⁵M

Thus, to obtain the 1.7x10⁻⁵M solutionyou need to:

<h3>Take 10.0mL of your original solution and dilute it to 100.0mL and then, take 5.0mL of this solution and dilute it in another flask to 100.0mL</h3>

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3 years ago

why do solids keep their shape and volume why do liquids keep only volume and why do gases not keep either shape or volume

kodGreya [7K]

Solids always have definite shape and definite volume because their particles are packed together. Liquids have a definite volume but not definite shape, because their particles still kinda tight but able to move around, and gases don’t have a definite shape nor volume, because their particles are crazy and go everywhere

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(c) O2 gas is transferred from a 3 L vessel containing oxygen at 4 atm to an evacuated 20 L vessel at a constant temperature of

Fudgin [204]

Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

$P x V = k$

Therefore, for this problem the step by step explanation is:

$P_{1} xV_{1} = P_{2} xV_{2}$

Clearing P2 and replacing

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arlik [135]

Answer:

wove oral visalize

Explanation:

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3 years ago