A proton in a uniform electric field moves along a straight line with constant acceleration. Starting from rest it attains a vel
1 answer:
a) The acceleration of the proton is
b) The time required to reach the given velocity is
Explanation:
a)
This is a motion at constant acceleration, so we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the proton in this problem, we have:
is the final velocity
is the initial velocity (it starts from rest)
is the distance covered
Solving for a, we find the acceleration:
b)
For this part, we can use the following suvat equation instead:
where:
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken for the velocity to change from u to v
We have here the following data:
is the final velocity
is the initial velocity (it starts from rest)
Solving for t, we find
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Answer:
(a) 1.58 V
(b) 0.0126 Wb
(c) 0.0493 V
Solution:
As per the question:
No. of turns in the coil, N = 400 turns
Self Inductance of the coil, L = 7.50 mH =
Current in the coil, i = A
where
Now,
(a) To calculate the maximum emf:
We know that maximum emf induced in the coil is given by:
For maximum emf, should be maximum, i.e., 1
Now, the magnitude of the maximum emf is given by:
(b) To calculate the maximum average flux,we know that:
(c) To calculate the magnitude of the induced emf at t = 0.0180 s: