1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mamaluj [8]
2 years ago
6

If a 50 N block experiences a force of kinetic friction of 11 N

Physics
1 answer:
ankoles [38]2 years ago
4 0

Answer:

F(friction) = μ M g         definition of frictional force

μ  = F / (M g) = 11 N / 50 N = .22

You might be interested in
In Part 6.2.2, you will determine the wavelength of the laser by shining the laser beam on a "diffraction grating", a set of reg
harkovskaia [24]

Answer:

λ = 2042 nm

Explanation:

given data

screen distance d = 11 m

spot s = 4.5 cm = 4.5 ×10^{-2} m

separation L = 0.5 mm = 0.5 ×10^{-3} m

to find out

what is λ

solution

we will find first angle between first max and central bright

that is tan θ = s/d

tan θ = 4.5 ×10^{-2}  / 11

θ = 0.234

and we know diffraction grating for max

L sinθ  = mλ

here we know m = 1  so put all value and find λ

L sinθ  = mλ

0.5 ×10^{-3}  sin(0.234)  = 1 λ

λ = 2042.02 ×10^{-9}  m

λ = 2042 nm

3 0
3 years ago
a new planet is discovered that has twice the earth’s mass and twice the earth’s radius. on the surface of this new planet, a pe
Irina18 [472]

Answer: 250n

Explanation:

The formula for gravitational force is: F = (gMm)/r^2

There are two factors at play here:

1) The mass of the planet 'M'

2) The radius 'r'

We can ignore the small M and the g, they are constants that do not alter the outcome of this question.

You can see that both M and r are double that of earth. So lets say earth has M=1 and r=1. Then, new planet would have M=2 and r=2. Let's sub these two sets into the equation:

Earth. F =  M/r^2 = 1/1

New planet. F = M/r^2 = 2/4 = 1/2

So you can see that the force on the new planet is half of that felt on Earth.

The question tells us that the force on earth is 500n for this person, so then on the new planet it would be half! So, 250n!

8 0
2 years ago
The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.10. The mass of the object i
denis-greek [22]

Answer:

Explanation:

1) Force Friction = Normal Force * Coefficient of Friction

Force Friction = Mass * Gravity * Coefficient of Friction

2) F = ma

Force = mass * acceleration

Force Friction (from #1) = mass * acceleration

acceleration = Force Friction / Mass

6 0
2 years ago
What is the perfect amount of sunlight needed on a planet.
gogolik [260]

Answer:

20 years Light.

Explanation:

There's no practical explanation just math's.

6 0
2 years ago
While operating a vehicle on any highway of this state, it is illegal to physically hold or support a wireless device with any p
algol13

Answer:

True

Explanation:

In Massachusetts it's illegal to drive while texting or on your phone.

3 0
3 years ago
Other questions:
  • A 9800-N automobile is pushed along a level road by four students who apply a total forward force of 600 N. Neglecting friction,
    11·1 answer
  • A comet is a
    12·1 answer
  • When a river flows into an ocean, it slows down and deposits materials in its alluvial fan/delta
    11·1 answer
  • A ship sets out to sail to a point 120 km due north. an unexpected storm blows the ship to a point 100 km due east of its starti
    10·1 answer
  • Find the speed of light in each of the following materials. (a) gallium phosphide m/s (b) carbon disulfide m/s (c) benzene
    11·1 answer
  • The water at Niagara Falls drops through a height of 55.0 m. If the water’s loss of gravitational potential energy shows up as a
    8·1 answer
  • What is the relationship between kinetic and potential energy of a falling object
    7·1 answer
  • Someone please helppp :|||
    5·2 answers
  • Direction of wind: from to​
    6·1 answer
  • 1. A Passenger car (m= 10.0 kg) and a flat car (m= 7.5 kg) collide and move off as
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!