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mel-nik [20]
2 years ago
14

A cylindrical can has height h and radius r both measured in cm. If the rate of increase of volume of the can with respect to he

ight equals the rate of increase of volume with respect to radius, what is the relationship between height and radius
Physics
1 answer:
Monica [59]2 years ago
4 0

Answer:

It simply means that the radius is directly proportional to the height.

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Answer: 40 cm x 200 cm

Explanation:

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You add 50 mL of water at 20C to 200 mL of water at 70C. What is the most likely final temperature of the mixture?
Veseljchak [2.6K]
100*20 + 200*80 = 300* T
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3 years ago
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1.Wave motion that is parallel to the wave direction is described 
Dafna1 [17]

Answer:

Explanation:

A wave is a phenomenon that travels through a material medium without any permanent effect on the medium. It can be classified as mechanical or electromagnetic waves. And the two major types are transverse and longitudinal.

From the given question;

1. Longitudinal waves e.g sound waves, waves in a spring'

2. Frequency (number of cycles per second).

3. Wavelength of the wave. Measured in meters.

4. Transverse waves e.g light waves, water waves.

5. Wave speed.

6. Electromagnetic waves e.g ultraviolet waves, X-rays etc.

7. Amplitude.

8. Hertz.

9. Rarefaction

10. Compression

7 0
2 years ago
At night a land breeze forms because
NemiM [27]

The wind will blow from the higher pressure over the water to lower pressure over the land causing the sea breeze. The sea breeze strength will vary depending on the temperature difference between the land and the ocean. At night, the roles reverse. The air over the ocean is now warmer than the air over the land.

not giving you the answer but hopefully this gives a hint

3 0
3 years ago
Calculate the displacement and velocity at 2.00 s for a ball thrown straight up with an initialvelocity of 15.0 m/s. Take the po
Hunter-Best [27]

Answer:

The displacement, velocity and time is 20.4 m, -4.52 m/s and 3.624 sec.

Explanation:

Given that,

Initial velocity =15.0 m/s

Height = 10 m

We need to calculate the displacement at 2 sec

Using equation of motion

s=ut-\dfrac{1}{2}gt^2+s_{0}

Put the value into the formula

s=15t-\dfrac{1}{2}\times9.8\times t^2+10

At 2 sec,

s=15\times2-\dfrac{1}{2}\times9.8\times4+10

s=20.4\ m

We need to calculate the time

Using equation of motion again

s=15t-\dfrac{1}{2}\times9.8\times t^2+10

At ground s = 0,

15t-\dfrac{1}{2}\times9.8\times t^2+10=0

4.9t^2-15t-10=0

t = 3.624\ sec

Neglect the negative term because the time is not negative

We need to calculate the velocity

Using formula of velocity

v=u-gt

v=15-9.8\times3.624

v=-4.52\ m/s

Hence, The displacement, velocity and time is 20.4 m, -4.52 m/s and 3.624 sec.

5 0
3 years ago
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