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Rudiy27
3 years ago
8

What is the current when a 71-W lamp is connected to 120 V?

Physics
1 answer:
vredina [299]3 years ago
5 0
Power = (voltage) · (current)

71 W  =  (120 V) · (current)

Divide each side by (120 V) :

Current = (71 W) / (120 V)  =  0.59167 Amperes

What I want to know is:  Where can I buy a 71-W light bulb ?
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When a coil is carrying a current of 25.0 A that is increasing at 145 A/s the induced emf in the coil has magnitude 3.70 mV.
Aleks04 [339]

Answer:

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b) 22.95 mV

Explanation:

Induced emf in a inductor is given by

E = L * di/dt, where

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di/dt if the rate of inductance

A

So we have

0.0037 = L * 145

L = 0.0037 / 145

L = 0.0000255

L = 25.5 µH

B

i(t) = 225t²

Recall that

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E = 25.5 µH * |225t²|

Differentiating with respect to t, we have

E = 25.5 * 2 * 225t

E = 25.5 * 450t

Solving for t = 2,we get

E = 25.5 * 450(2)

E = 25.5 * 900

E = 22950 µV or

E = 22.95 mV

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