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Lerok [7]
3 years ago
15

Consider two copper wires with the same cross-sectional area. Wire a is twice as long as wire b. How do the resistivities and re

sistances of the two wires compare?
Physics
1 answer:
wel3 years ago
6 0

Answer:

<em>from the equation 1 below, the ratio of the resistivity of wire b to its resistance is twice the ratio of the resistivity if wire A to its resistance.</em>

Explanation:

<em>R=(ρL)/A</em>

<em>A =(ρL)/R</em>

<em>Where A is cross sectional area,</em>

<em>ρ is the resistivity</em>

<em>L is length of wire</em>

<em>R is resistance of wire.</em>

from the question the two wires have same cross sectional area.

Aa =Ab  ; hence

(ρaLa)/Ra  = (ρbLb)/Rb

La =2Lb

(ρa*2Lb)/Ra  = (ρbLb)/Rb

(2ρa)/Ra  = (ρb)/Rb

ρb/Rb  =  2* ρa/Ra        ...................                equ 1

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