If the liquid is denser than the coin, then the coin will eventually
come to rest floating, with part of it above the surface of the liquid.
That's exactly the situation if you drop the coin into mercury.
Density of copper . . . 8.96 gm/cm³
iron . . . 7.87
zinc . . . 7.13
silver . . 10.5
nickel . . .8.91
lead . . . 11.4
Density of mercury . . . 13.53 gm/cm³ !
Answer:
Ratio is 7.58
Explanation:
At the bottom of the circle, the net force is given by
where m is mass of plane, v is the speed of plane, r is vertical circle radius
Since W=mg, dividing left side by W and right side by mg we obtain
=7.578096
=7.58
Considering that =7.58 which is greater than 2, the pilot is advised to wear the anti-G suit
Answer:
Positive charge is attracted to the neutral object.
Explanation:
Recall ; Like charges repel, unlike charges attract. This phrase simply means (positive (+) is attracted to negative (-ve) and vuc versa while both positive, positive and negative, negative charge repel.
For a neutral object. The quantity of positive charge equals the quantity of negative charges. This simply means a neutral object contains charges as well, which are usually scattered or randomly aligned.
Therefore, when a positive charge is brought near a neutral body, the order of alignment of the charges change, with the negative charge all moving towards the direction of the positively charged body and the positive charges in the neutral body aligning in the opposite direction.
Answer:
an apple falling off a tree
Explanation:
Answer:
(a) 5.0 kg
(b) 10 kg
Explanation:
Draw a free body diagram for each block. There are 4 forces on block A:
Weight force mAg pulling down,
Normal force N pushing up,
Tension force T pulling right,
and friction force Nμ pushing left.
There are 2 forces on block B:
Weight force mBg pulling down,
and tension force T pulling up.
Whether the system is just starting to move, or moving at constant speed, the acceleration is 0.
Sum of forces on B in the -y direction:
∑F = ma
mBg − T = 0
mBg = T
Sum of forces on A in the +y direction:
∑F = ma
N − mAg = 0
N = mAg
Sum of forces on A in the +x direction:
∑F = ma
T − Nμ = 0
T = Nμ
Substitute:
mBg = mAg μ
mA = mB / μ
(a) When the system is just starting to move, μ = 0.40.
mA = 2.0 kg / 0.40
mA = 5.0 kg
(b) When the system is moving at constant speed, μ = 0.20.
mA = 2.0 kg / 0.20
mA = 10 kg