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Ivahew [28]
3 years ago
9

Which one of the following concepts explains why heavy nuclei do not follow the N = Z line (or trend) in the figure? A Transmuta

tion B. Coulomb repulsion C. Particle-wave duality D. Pauli exclusion principle E. Heisenberg uncertainty principle
Physics
1 answer:
NikAS [45]3 years ago
7 0

Answer:

Option B. Coulomb Repulsion

Explanation:

The reason for the heavy nucleus not being able to follow the trend or the N= Z line is because of the fact that as the atomic number, Z of an atom increases, the number of protons inside the atom also increases. Since the neutrons are charge less particles whereas the protons are positively charged particle and hence as these increases in number there is an increase in the repulsive force between the like charges, i.e., positively charged protons which is Coulomb repulsion.

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If a car accelerates uniformly from rest to 15 meters
Talja [164]

Answer:

1.125m/s^2

Explanation:

Since acceleration is defined as the rate of change in velocity with respect to time. Mathematically

v^2= u^2+2as

Where a,v,u and s are the acceleration, final velocity, initial velocity and distance respectively.

a = ?

u = 0m/s

v = 15m/s

s = 100m

Substituting the values into the formula above

v^2= u^2+2as

15^2=0^2+2×a×100

225= 0+200a

225= 200a

Divide both sides by 200

225/200 = 200a/200

a= 1.125m/s^2

Hence the acceleration of the car is 1.125m/s^2.

Note that the car accelerated uniformly from rest, that was why the initial velocity was 0m/s

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Which angle (A, B, or C) is the diffraction angle?
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3 years ago
The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 8.0 s. At thi
alisha [4.7K]

Answer:

The total number of revolution is 50 rev.

Explanation:

Given that,

Angular speed = 5.0 rev/s

Time = 8.0 s

We need to calculate the angular acceleration

Using equation of angular motion

\omega_{f}-\omega_{i}=\alpha t

Put the value into the formula

5.0-0=\alpha\times8.0

\alpha=\dfrac{5.0}{8.0}

\alpha=0.625\ rev/s^2

We need to calculate the angular displacement

Using equation of angular motion

\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2

Put the value into the formula

\theta=0+\dfrac{1}{2}\times0.625\times(8.0)^2

\theta=20\ rev

Now, The washer coming to rest from top spin

We need to calculate the angular acceleration

Using equation of angular motion

\omega_{f}-\omega_{i}=\alpha t

\alpha=\dfrac{\omega_{f}-\omega_{i}}{t}

\alpha=\dfrac{0-5}{12}

\alpha=−0.4167\ rev/s^2

We need to calculate the angular displacement

Using formula of displacement

\theta'=\omega_{i}t+\dfrac{1}{2}\alpha t^2

Put the value into the formula

\theta'=5\times12+\dfrac{1}{2}\times(-0.4167)\times12^2

\theta'=30\ rev

We need to calculate the total number of revolution

\theta''=\theta+\theta'

\theta''=20+30

\theta''=50\ rev

Hence, The total number of revolution is 50 rev.

5 0
4 years ago
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