Explanation:
constantly shallow sea tho not exactly sure
The problem corresponds to the motion of a projectile (the salmon), with initial speed
, initial direction
and vertical acceleration
downward. The two equations which gives the horizontal and vertical position of the salmon at time t are
(1)
(2)
We can solve the problem by requiring Sx=3.16 m and Sy=0.379 m, the data of the problem.
Solving eq.(1) for t:

And substituting this expression of t into eq.(2), we get the following expression for
:

And substituting the numbers into the equation, we find

I think it becomes a negative integer?
When water changes to ice, its density decreases and its volume increases.
A ) v = 567 - 33 = 534 km/h
v = d / t ⇒ t = d / v
t = 780 km / 534 km/h = 1.46 h
b ) v = 567 + 33 = 600 km/h
t = 780 km / 600 km/h = 1.3 h
c ) v = (567² +33²) ^(1/2) = √320,400 = 566 km/h
t = 780 km/ 566 km/h = 1.378 h