Answer:
The amount of work the factory worker must to stop the rolling ramp is 294 joules
Explanation:
The object rolling down the frictionless ramp has the following parameters;
The mass of the object = 10 kg
The height from which the object is rolled = 3 meters
The work done by the factory worker to stop the rolling ramp = The initial potential energy, P.E., of the ramp
Where;
The potential energy P.E. = m × g × h
m = The mass of the ramp = 10 kg
g = The acceleration due to gravity = 9.8 m/s²
h = The height from which the object rolls down = 3 m
Therefore, we have;
P.E. = 10 kg × 9.8 m/s² × 3 m = 294 Joules
The work done by the factory worker to stop the rolling ramp = P.E. = 294 joules
Cups
teaspoon
tablespoon
liters
milliliters
gallons
pints
tons
inches
Answer:
he average speed for the airplane is 558 km/hr
Explanati
Answer:
The velocity of the ship relative to the earth V = 9.05 
Explanation:
The local ocean current is = 1.52 m/s
Direction 
= 40°
Velocity component in X - direction 
= 1.52 
°
= 1.164
Velocity component in Y - direction 
= 8 + 1.52 
°
= 8.97
The velocity of the ship relative to the earth
Put the values of and we get,
⇒ 
⇒ V = 9.05
This is the velocity of the ship relative to the earth.
Sample:
As soon as the lightning is seen, sound travels in the air for several kilometers until it eventually reaches the observer.
