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goldfiish [28.3K]

3 years ago

9

The splitting of a(n) ________ to produce energy is called a fission reaction. A. atom B. proton C. neutron D. molecule The spli

tting of an atom to produce energy is called a fission reaction.

1 answer:

nata0808 [166]3 years ago

6 0

A.atom splits to produce energy is called fission reaction

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When glass is formed, which of these takes place FIRST?

nekit [7.7K]

The answer is A) the sand turns to liquid

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3 years ago

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(a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 32º ramp at a speed

stiks02 [169]

a) 7 buses

b) 6.8 m

Explanation:

a)

The motion of the motorcycle is a projectile motion, so it consists of 2 independent motions:

- A uniform motion along the horizontal direction

- A uniformly accelerated motion along the vertical direction

The initial components of the velocity of the motorcycle are:

$v_x = u cos(32^{\circ})=(40.0)(cos 32^{\circ})=33.9 m/s\\v_y = u sin(32^{\circ})=(40.0)(sin 32^{\circ})=21.2 m/s$

The equation for the vertical motion of the motorcycle is

$y=h+u_y t - \frac{1}{2}gt^2$

where

y is the altitude at time t

h is the initial height

$g=9.8 m/s^2$ is the acceleration due to gravity

The bus top is at the same height of the initial ramp, so we have

$y=h$

And therefore, we can solve the equation for t, to find the time of flight:

$0=u_y t - \frac{1}{2}gt^2\\t(u_y-\frac{1}{2}gt)=0\\t=\frac{2u_y}{g}=\frac{2(21.2)}{9.8}=4.33 s$

Now we find what is the horizontal distance covered by the motorcycle in its jump, which is given by:

$d=v_x t = (33.9)(4.33)=146.8 m$

And since each bus has a length of L = 20.0 m, the number of buses that the motorcycle can clear with its jump is:

$n=\frac{d}{L}=\frac{146.8}{20}=7.34$

So, 7 buses.

b)

In the previous problem, we saw that the total range of the motion of the motorcycle is

$d=146.8 m$

And we said that this corresponds to 7 buses.

Each bus has a length of

L = 20 m

So, the total length of 7 buses is

$L' = 7L=7(20)=140 m$

Therefore, the range of the motorcycle is greater than the length of the buses by:

$\Delta x = d-L'=146.8-140 = 6.8 m$

which means he will miss the last bus by 6.8 meters.

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3 years ago

Which law describes the magnetic field in a nonlinear wire?

mariarad [96]

Lenz's law describes the magnetic field of non linear wire

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3 years ago

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Suppose you are pushing on a crate across a floor as shown below. Assume the friction force is 47.0 N. How much time will it tak

Mandarinka [93]

Answer:

6.2 seconds

Explanation:

Using Newton's second law, ∑F=ma, we know the net force acting on the object is Force applied-Force of friction. The net force is 203 N. Newton's second law requires the mass of an object, not the weight force, so we will have to calculate the mass. We know that m*g=weight force, in this case, solve for the mass and you will get 210 kg. Now that we have the value of the net force and the mass, we can solve for acceleration. $\frac{F}{m}=a$ =0.967 m/s^2. Now, since we have the acceleration, initial velocity(0 m/s), and the final velocity (6m/s) we will use these to solve for time using the kinematic equation Vf=Vi + at. Plug in the values we know and solve for time and you will get 6.2 seconds

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2 years ago

A 15.0kg block is dragged over a rough, horizontal surface by a 70.0-N force acting at 20.0 degrees above the horizontal. The bl

Masteriza [31]

Answer:

$W=70 * 5cos20 = 328.89 J$

$W_n = 0$

$W_g=0$

$W_f= -184.59J$

Work done is 0

Explanation:

From the question we are told that

Weight of block =15.0kg

Force acting on the block = 70.0N

At an angle of 20 degree

Displacement of block is 5m

Coefficient of kinetic friction 0.3

b) Generally work done by force is give by $W=fdcos \theta$

therefore

$W=70 * 5cos20 = 328.89 J$

c) there is no work done by the normal force in this scenario because

normal force in this case is perpendicular to the displacement of the motion

$W_n = 0$

d) The displacement in the vertical direction is 0

Therefore the gravitational work done is 0 $W_g=0$

e)Generally in finding work done by friction we first find frictional force

Mathematically the equation for frictional force is given $f = \alpha N$

Given that

$N=mg-Fsin20$

$N= 15.0*9.8 - 70 sin20$

$N=123 N$

$f=0.3* 123.06 = 36.92N$

Mathematically solving to get work done by frictional force $W_f$

$W_f= -fd\\W_f = -36.92 * 5$

$W_f= -184.59J$

the frictional force work done is $W_f= -184.59J$

3 0

3 years ago