A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and
1 answer:
Answer:
a)
b)
Explanation:
From the question we are told that:
Density
Velocity of wind
Dimension of rectangle:50 cm wide and 90 cm
Drag coefficient
a)
Generally the equation for Force is mathematically given by
Therefore Torque
b)
Generally the equation for torque due to weight is mathematically given by
Where
Therefore
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(a) 25lx
(b) 11.11lx
<u>Explanation:</u>
Illuminance is inversely proportional to the square of the distance.
So,
where, k is a constant
So,
(a)
If I = 100lx and r₂ = 2r Then,
Dividing both the equation we get
When the distance is doubled then the illumination reduces by one- fourth and becomes 25lx
(b)
If I = 100lx and r₂ = 3r Then,
Dividing equation 1 and 3 we get
When the distance is tripled then the illumination reduces by one- ninth and becomes 11.11lx
Answer:
a) The magnitude of the electric charge that a 60-kg human must have to overcome weight is 3.923 coulombs and its sign is negative.
b) The force of repulsion between two people is newtons. The use of the earth's electric field a feasible means of flight is not feasible since electric force of repulsion would destroy human body before taking advantage of any possible flight skill.
Explanation:
a) From Second Newton's Law, we form this equation of equilibrium:
(Eq. 1)
Where:
- Electrostatic force exerted on human, measured in Newton.
- Weight of the human, measured in Newton.
If we consider that human can be represented as a particle and make use of definitions of electric field and weight, the previous equation is expanded and electric charge is cleared afterwards:
(Eq. 2)
- Electric field, measured in Newtons per Coloumb.
- Mass, measured in kilograms.
- Gravity acceleration, measured in meters per square second.
- Electric charge, measured in Coulomb.
As electric field of the Earth is directed in toward the center of the planet, that is, in the same direction of gravity, electric field must be a negative value. If we know that ,
and
, the charge that a 60-kg human must have to overcome weight is:
The magnitude of the electric charge that a 60-kg human must have to overcome weight is 3.923 coulombs and its sign is negative.
b) The electric force of repulsion between two people with the same charge calculated in part (a) is determined by Coulomb's Law, whose definition we proceed to use:
(Eq. 3)
Where:
- Electrostatic constant, measured in Newton-square meter per square Coulomb.
- Electric charge, measured in Coulomb.
- Distance between two people, measured in meters.
If we know that ,
and
, then the force of repulsion between two people is:
The force of repulsion between two people is newtons. The use of the earth's electric field a feasible means of flight is not feasible since electric force of repulsion would destroy human body before taking advantage of any possible flight skill.