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masya89 [10]
3 years ago
10

(i) 1s 2 2s 2 2p 6 3s 1 (ii) 1s 2 2s 2 2p 6 3s 2 (iii) 1s 2 2s 2 2p 6 3s 2 3p 1 (iv) 1s 2 2s 2 2p 6 3s 2 3p 4 (v) 1s 2 2s 2 2p 6

3s 2 3p 5 The electron configuration of the atom that is expected to have a positive electron affinity is ________.
Chemistry
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

 (V) 1s 2 2s 2 2p 6 3s 2 3p 5

Explanation:

Electron Affinity can be defined as the energy associated with a neutral atom, when an electron is added to form a negative ion.

1s 2 2s 2 2p 6 3s 2 3p 5 , is the electronic configuration of Chlorine.

The electron affinity is positive because it is an exorthermic reaction, meaning that, energy was released during the addition of an electron to the atom.

Cl (g)  +  e-   ------->  Cl- (g)    = -349KJ/mol

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When measuring water using the graduated pipette, the mass of beaker and the water is 23.670 g. If the empty beaker weighs 13.71
Arturiano [62]

Answer:

The volume of water measured is 10mL

Explanation:

Given;

Mass of mass of beaker and the water = 23.670 g

Mass of empty beaker = 13.712 g

Then, mass of water only = Total mass of of beaker and the water minus Mass of empty beaker

mass of water only = 23.670 g - 13.712 g = 9.958 g

Density = mass/volume

Given density of water = 0.9982071 g/mL

Density of water = Mass of water/ Volume of water

Then, Volume of water =  Mass of water/Density of water

Volume of water = 9.958 g/0.9982071 g/mL

Volume of water = 9.975886 mL ≅ 10mL

Therefore, The volume of water measured is 10mL

6 0
4 years ago
7. If you start with 3.20 mol of Li3N and 9.0 mol water, how many moles of NH3 will be formed?
pickupchik [31]

Taking into account the reaction stoichiometry, 3 moles of NH₃ will be formed.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Li₃N + 3 H₂O → NH₃ + 3 LiOH

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Li₃N: 1 mole
  • H₂O: 3 moles
  • NH₃: 1 mole
  • LiOH: 3 moles

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Li₃N reacts with 3 moles of H₂O, 3.20 moles of Li₃N reacts with how many moles of H₂O?

moles of H_{2} O=\frac{3.2 moles of Li_{3}Nx 3 moles of  H_{2} O}{1 mole of Li_{3}N}

<u><em>moles of H₂O= 9.6 moles</em></u>

But 9.6 moles of H₂O are not available, 9 moles are available. Since you have less moles than you need to react with 3.20 moles of Li₃N, H₂O will be the limiting reagent.

<h3>Mass of NH₃ formed</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 3 moles of H₂O form 1 mole of NH₃, 9 moles of H₂O form how many moles of NH₃?

molesof NH_{3} =\frac{9 moles H_{2} Ox1 mole of NH_{3}}{3 moles H_{2} O}

<u><em>moles of NH₃= 3 moles</em></u>

Finally, 3 moles of NH₃ will be formed.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

7 0
2 years ago
A spaceship is traveling through space. Suddenly, its speed increases. What can
asambeis [7]

Answer:

A. The kinetic energy increases as its speed increases.

Explanation:

The kinetic energy of an object is energy possessed by an object by virtue of its motion.

Now, kinetic energy of a moving body is given by;

KE = 1/2 mv^2

Where;

m = mass of the body

v = velocity (speed) of the body

It follows that if the mass of the spaceship is constant, a sudden increase in speed leads to a corresponding increase in the kinetic energy of the spaceship in accordance with the relationship show above.

6 0
3 years ago
100gm of a 55% (M/M) nitric acid solution is to be diluted to 20% (M/M) nitric acid.
yawa3891 [41]

Volume of H₂O added = 175 ml

<h3>Further explanation</h3>

Given

100 gm of a 55% (M/M)  and 20% (M/M) nitric acid solution

Required

waters added

Solution

starting solution

mass H₂O = 45%=45 g

%mass of H₂O in new solution = 100%-20%=80%

Can be formulated for %mass H₂O :

\tt \dfrac{45+x}{100+x}=80\%\\\\45+x=0.8(100+x)\\\\45+x=80+0.8x\\\\35=0.2x\rightarrow x=175~g

For water mass=volume(density = 1 g/ml)

So volume added = 175 ml

7 0
3 years ago
Please help I will give brainliest!
aleksklad [387]
I believe it’s the 3rd option
6 0
3 years ago
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