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alisha [4.7K]
3 years ago
6

Ball A was carried to the top of a hill in a straight line, while ball B was carried in a longer, zigzag path. At the top of the

hill, both balls were left at rest. A student draws a graph that depicts each ball's final potential energy. Which statement describes the final potential energy of the balls?(1 point)
Both balls have equal potential energy.

Neither ball has any potential energy.

Ball A has more potential energy.

Ball B has more potential energy.
Physics
2 answers:
lisov135 [29]3 years ago
6 0

Answer: 1. Both balls have equal potential energy.

2. Potential energy would decrease, while total mechanical energy would remain constant.

3. A slide

4. Mass is eliminated when equating gravitional potential energy with kinetic energy.

5. 1/2 mv^2 = 1/2 kx^2

Explanation:

I did the test by pure guess and failed but oh well, got the answers

marissa [1.9K]3 years ago
5 0

Answer: equal

Explanation:

Don’t know why honestly

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A straight wire segment 2 m long makes an angle of 30degrees with a uniform magnetic field of 0.37 T. Find the magnitude of the
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What force, in newtons, must you exert on the balloon with your hands to create a gauge pressure of 62.5 cm H2O, if you squeeze
yulyashka [42]

Answer:54.70 N

Explanation:

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Gauge Pressure of 62.5 cm of H_2O

i.e. h=62.5 cm =0.625 m

Effective area A=51 cm^2

initial Pressure= 1 atm=101.325 kPa

Gauge Pressure P=\rho gh

\rho =density\ of\ water =1000 kg/m^3

P_{gauge}=1000\times 9.8\times 0.625=5.937 kPa

Force creates a pressure of P_1 which will be equal to Gauge Pressure

P_1=\frac{F}{A}

P_1=P_{gauge}

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6 0
3 years ago
A child on a tricycle is moving at a speed of 1.40 m/s at the start of a 2.25 m high and 12.4 m long incline. The total mass is
goblinko [34]

Answer:

The work done by the child as the tricycle travels down the incline is 416.96 J

Explanation:

Given;

initial velocity of the child, v_i = 1.4 m/s

final velocity of the child, v_f = 6.5 m/s

initial height of the inclined plane, h = 2.25 m

length of the inclined plane, L = 12.4 m

total mass, m = 48 kg

frictional force, f_k = 41 N

The work done by the child is calculated as;

\Delta E_{mech} = W - f_{k} \Delta L\\\\W = \Delta E_{mech}  + f_{k} \Delta L\\\\W = (K.E_f - K.E_i) + (P.E_f - P.E_i) + f_{k} \Delta L\\\\W = \frac{1}{2} m(v_f^2 - v_i^2) + mg(h_f - h_i) + f_{k} \Delta L\\\\W = \frac{1}{2} \times 48(6.5^2 - 1.4^2) + 48\times 9.8(0-2.25) + (41\times 12.4)\\\\W = 966.96  \ - \ 1058.4 \ + \ 508.4\\\\W = 416.96 \ J

Therefore, the work done by the child as the tricycle travels down the incline is 416.96 J

5 0
3 years ago
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