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alisha [4.7K]
3 years ago
6

Ball A was carried to the top of a hill in a straight line, while ball B was carried in a longer, zigzag path. At the top of the

hill, both balls were left at rest. A student draws a graph that depicts each ball's final potential energy. Which statement describes the final potential energy of the balls?(1 point)
Both balls have equal potential energy.

Neither ball has any potential energy.

Ball A has more potential energy.

Ball B has more potential energy.
Physics
2 answers:
lisov135 [29]3 years ago
6 0

Answer: 1. Both balls have equal potential energy.

2. Potential energy would decrease, while total mechanical energy would remain constant.

3. A slide

4. Mass is eliminated when equating gravitional potential energy with kinetic energy.

5. 1/2 mv^2 = 1/2 kx^2

Explanation:

I did the test by pure guess and failed but oh well, got the answers

marissa [1.9K]3 years ago
5 0

Answer: equal

Explanation:

Don’t know why honestly

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Given the nuclear equation:
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This is a nuclear fission reaction, in which a larger nucleus is bombarded with a neutron to make it break down into two smaller nuclei and release energy.
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3 years ago
A motorboat maintained a constant speed of 15 miles per hour relative to the water in going 10 miles upstream and then returning
Lesechka [4]

Answer:

speed of current is 5 mile/hr

Explanation:

GIVEN DATA:

speed of motorboat = 15 miles/hr relative with water

let c is speed of current

15-c is speed of boat at  upstream

15+c is speed of boat at downstream

we know that

travel time=distance/speed

\frac{10}{15-c} +\frac{10}{15+c} = 1.5

150+10c+150-10c=1.5(15-c)(15+c)

300=1.5(225-c^2)

300=337.5-1.5c^2

200=225-c^2

c^2=25

c = 5

so speed of current is 5 mile/hr

6 0
3 years ago
A total positive charge of 12.00 mC is evenly distributed on a straight thin rod of length 6.00 cm.
Gala2k [10]
It’s not in English can you change it please
3 0
3 years ago
Your friend, who is in a field 100 meters away from you, kicks a ball towards you with an initial velocity of 16 m/s. Assuming t
LekaFEV [45]

Answer:

Time, t = 5.355 seconds

Explanation:

Given the following data;

Distance = 100 m

Initial velocity = 16 m/s

Deceleration = 1 m/s²

To find the time, we would use the second equation of motion;

But since the ball is decelerating, it's acceleration would be negative.

S = ut + ½at²

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

100 = 16t - 0.5t²

200 = 32t - t²

t² + 32t - 200 = 0

Solving the quadratic equation using the quadratic formula;

The quadratic equation formula is;

x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a}

Substituting into the equation, we have;

x = \frac {-32 \; \pm \sqrt {32^{2} - 4*1*(-200)}}{2*1}

x = \frac {-32\pm \sqrt {1024 - (-800)}}{2}

x = \frac {-32 \pm \sqrt {1024 + 800}}{2}

x = \frac {-32 \pm \sqrt {1824}}{2}

x = \frac {-32 \pm 42.71}{2}

x_{1} = \frac {-32 + 42.71}{2}

x_{1} = \frac {10.71}{2}

x1 = 5.355

We do not need the negative value of x, so we proceed.

Therefore, time = 5.355 seconds

3 0
3 years ago
A conducting loop has an area of 0.065 m2 and is positioned such that a uniform magnetic field is perpendicular to the plane of
aev [14]

Answer:

initial magnetic field  1.306 T

Explanation:

We have given area of the conducting loop A=0.065m^2

Emf induced = 1.2 volt

Initial magnetic field B = 0.3 T

Time dt = 0.087 sec

We know that induced emf is given by e=\frac{d\Phi }{dt}=-A\frac{db}{dt}

1.2=0.065\times \frac{db}{0.087}

db=1.606T

So initial magnetic field = 1.606-0.3= 1.306 T

5 0
3 years ago
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