Answer:
the maximum height of Joe's ball will be 4 times Bill's ball.
Explanation:
let bill's velocity be v then Joe's velocity is 2v.
and initial velocities of both bill and Joe are 0
for Bill
for Joe
thus we can write that
h'=4h
the maximum height of Joe's ball will be 4 times Bill's ball.
Answer:
The correct answer is option a.
Explanation:
Conservation of momentum :
Where :
= masses of object collided
= initial velocity before collision
= final velocity after collision
We have :
Two equal-mass carts roll towards each other.
Initial velocity of 
Initial velocity of 
(opposite direction)
Final velocity of 
(same direction )
Final velocity of 
(same direction)
v = 0.5 m/s
rg135
The speed of the carts after their collision is 0.5 m/s.
The visible radiation produced by new stars within a molecular cloud get absorbed by dust grains and heats up the cloud
A molecular cloud is an interstellar cloud of gas and dust in which molecules can form, the most common of which is hydrogen .
The formation of stars occurs exclusively within molecular clouds because of their low temperatures and high densities, because the gravitational force acting to collapse the cloud must exceed the internal pressures that are acting "outward" to prevent a collapse.
Visible radiation are absorbed by dust grains and heats up the cloud as it cannot penetrate through the cloud instead get absorbed by the cloud . Newly formed stars are visible nearby, their images reddened by blue light which got scattered by the pervasive dust.
To learn more about molecular clouds here
brainly.com/question/3459894
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Answer:
A. F=107.6nN
B. Repulsive
Explanation:
According to coulombs law, the force between two charges is express as
F=(Kq1q2) /r^2
If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.
Note the constant K has a value 9*10^9
Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m
If we substitute values we have
F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)
F=(282.4×10^-9)/2.6244
F=107.6×10^-9N
F=107.6nN
B. Since the charges are both positive, the force is repulsive
Answer:
W = 112.76MJ
Explanation:
the work is:
where 
is the force executed in the direction of the displacement and the d the displacement.
so:
W = 12000Ncos(20)(10000)
we use the cos of the angule because it give us the proyection in the axis x of the force, that means the force in the direction of the displacement.
W = 112.76MJ
