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3 years ago

Can someone please tell me the answer

Physics

1 answer:

Anna35 [415]3 years ago

8 0

So here the red ball is initially stationary so V2=0m/s. Plus for the sake of rules the mass must be converted into kg. Initial momentum would equal the final momentum. Make an equation out of it and get the answer.

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Blank is the the decrease in a materail's volume when it's blank decrease

natulia [17]

Answer:

Explanation:

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2 years ago

Find the intensity of electromagnetic radiation at the surface of the sun (radius r=R=6.96×105kmr=R=6.96×105km). Ignore any scat

alisha [4.7K]

Answer:

$I = 4.46*10^{16}W/m^2$ .

Explanation:

Intensity $I$ of the electromagnetic radiation is given by

$I = \dfrac{P}{4\pi r^2},$

where $r$ is the distance from the EM source (the center of the sun, in our case), and $P$ is the power output of the sun and it has the value

$P = 3.9 *10^{26}W.$

Since the radius of the sun in meters is $r = 6.96*10^8km$ , the intensity $I$ of the electromagnetic radiation at the surface of the sun is

$I = \dfrac{3.9*10^{26}W}{4\pi (6.96*10^8m)^2}\\\\\boxed{ I = 4.46*10^{16}W/m^2}$

The intensity of the electromagnetic radiation at the surface of the sun is $I = 4.46*10^{16}W/m^2$ .

7 0

2 years ago

If a 10kg block is at rest on a table and a 1200N force is applied in the eastward direction for 10 seconds, what is the acceler

gavmur [86]

Answer:

a = 120 m/s²

Explanation:

We apply Newton's second law in the x direction:

∑Fₓ = m*a Formula (1)

Known data

Where:

∑Fₓ: Algebraic sum of forces in the x direction

F: Force in Newtons (N)

m: mass (kg)

a: acceleration of the block (m/s²)

F = 1200N

m = 10 kg

Problem development

We replace the known data in formula (1)

1200 = 10*a

a = 1200/10

a = 120 m/s²

6 0

2 years ago

85POINTS ASAP!!!!!!!!!!!!!!

alexgriva [62]

The andwer of tye question is 3O2

6 0

2 years ago

Read 2 more answers

PLEASE HELP

Sergeu [11.5K]

The vertical component of the initial velocity is $v_0_y = \frac{y}{t} + \frac{1}{2} gt$

The horizontal component of the initial velocity is $v_0_x = \frac{x}{t}$

The horizontal displacement when the object reaches maximum height is $X = \frac{xy}{gt^2} + \frac{x}{2}$

The given parameters;

the horizontal displacement of the object, = x

the vertical displacement of the object, = y

acceleration due to gravity, = g

time of motion, = t

The vertical component of the initial velocity is given as;

$y = v_0_yt - \frac{1}{2} gt^2\\\\v_0_yt = y + \frac{1}{2} gt^2\\\\v_0_y = \frac{y}{t} + \frac{1}{2} gt$

The horizontal component of the initial velocity is calculated as;

$x = v_0_xt\\\\v_0_x = \frac{x}{t}$

The time to reach to the maximum height is calculated as;

$T = \frac{v_f_y -v_0_y}{-g} \\\\T = \frac{-v_0_y}{-g} \\\\T = \frac{v_0_y}{g} \\\\T = \frac{1}{g} (v_0_y)\\\\T = \frac{1}{g} (\frac{y}{t} + \frac{1}{2} gt)\\\\T = \frac{y}{gt} + \frac{1}{2} t$

The horizontal displacement when the object reaches maximum height is calculated as;

$X= v_0_x \times T\\\\X= \frac{x}{t} \times (\frac{y}{gt} + \frac{1}{2} t)\\\\X = \frac{xy}{gt^2} + \frac{x}{2}$

Learn more here: brainly.com/question/20689870

8 0

2 years ago