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MArishka [77]
3 years ago
8

A secondary battery is a battery that A. has been repaired following damage. B. can only be discharged once. C. is supplied with

a fuel. D. can be discharged and recharged.
Physics
1 answer:
NemiM [27]3 years ago
3 0

Answer:D

Explanation:

A secondary battery or rechargeable battery is a battery that can be discharged and recharged.

It is an elcetrochemical cell which involve redox reaction i.e. oxidation and reduction. Oxidation is a process of loosing the electrons while reduction involves gaining of electron.

During discharging battery act as galvanic cell in which Chemical energy is converted into Electrical energy.

During Charging battery act as Electrolytic cell in which Electrical energy is converted in to chemical energy.

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Net work = Work done - Amount Work release
W = 106 - 74 = 32 J

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Hope this helps!
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Johannes Kepler, an apprentice of Brahe, believed in the heliocentric universe but rejected past astronomers' belief in
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Block A, with mass mA, is initially at rest on a horizontal floor. Block B, with mass mB, is initially at rest on the horizontal
nexus9112 [7]

Answer:

(E) μs(mA +mB)g

Explanation:

We can apply for mB:

∑ Fx = mB*a   (→)

⇒  Ffriction = mB*a   ⇒  a = Ffriction / mB = μs*N / mB

⇒ a = μs*(mB*g) / mB  ⇒   a = μs*g    (acceleration of the system)

Now, for mA we have

∑ Fx = mA*a   (→)

F - Ffriction = mA*a      ⇒  F = mA*a + Ffriction  

⇒     F = mA*(μs*g) + μs*(mB*g)   ⇒   F = μs*g*(mA + mB)

We must know that the friction acts only between the two blocks

8 0
3 years ago
Convert 9.75 millimeters to centimeters.
Alex777 [14]
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4 0
3 years ago
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Gold has a specific heat of 0.130 J/g*C. If 195 joules of heat are added to 15 grams of gold how much does the temperature of th
Anna71 [15]

The correct answer to the question is :  100\ ^0C

EXPLANATION :

As per the question, the specific heat of gold is given as c = 0.130\ J/g^0C

The heat given to the gold dQ = 195 J

The mass of the gold is given as m = 15 gram.

We are asked to calculate the change in temperature.

Let the change in temperature is dT.

We know that dQ = mcdT

                      dT=\ \frac{dQ}{mc}

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                             =\ 100\ ^0C                   [ANS]

Hence, the change in temperature is 100 degree celsius.

5 0
4 years ago
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