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Schach [20]
3 years ago
7

WILL GIVE BRAINLIEST!!! (100 points) cliff divers in hawaii dive from 65 meter high cliffs. the rocks at the base of the cliff p

rotrude 27 meters beyond the edge of the cliff. which sketch is the correct representation of the problem?
answer asap please:)

Physics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

choice 3 because the arrow has to be downward for as. and if the divers want to live, the vx has to be going right and not 0 or they would hit the rocks. I hope it's right!

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What produces the distinctive flame color of different substances when they are ignited?
shepuryov [24]

Answer:

Electrons in different metals

Explanation:

When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy.  The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.

4 0
3 years ago
A car advertisement claims their car can go from a stopped position to 60 miles per hour in 5 seconds. The advertisement is desc
Komok [63]

Answer:

Acceleration

Explanation:

The advertisement is describing the acceleration of the car.

Acceleration is the rate of change of velocity per unit of time. It can be expressed mathematically as;

 Acceleration  = \frac{v  - u}{t}  

 v is the final velocity

 u is the initial velocity

 t is the time taken

 Any quantity that specifies the rate of change of velocity of a body within a given time frame is describing its acceleration.

5 0
3 years ago
A ball is thrown vertically upward with an initial speed of 18 m/s. then, 0.73 s later, a stone is thrown straight up (from the
svetoff [14.1K]

Solution:

 the boll,  

y = Vo t + ½ g t²  

y = 18 t + ½ (-9.8) t²  

and the second one,  

y = Vo t + ½ g t²  

y = 30(t – 0.735) + ½ (-9.8)(t - 1.0.735)²  

the stone and the ball will pass each other if,  

y = y  

18 t + ½ (-9.8) t² = 30(t – 0.73) + ½ (-9.8)(t - .0.73)²  

t = 1.8196 sec  

y = 18 t + ½ (-9.8) t²  

y = 18(1.8196) + ½ (-9.8)(1.8196)²  

y = 16.5292 m above initial point

Thus, this the required solution.

 

7 0
3 years ago
Ablok slides on ahorizonted sur fors which has been lubricated with heavy oil such that the blok soffers a viscous resistance th
svetoff [14.1K]

Answer:

v = (v_0^{\frac{3}{2}}-\frac{3cx}{2m})^\frac{2}{3}

x = \frac{2m}{c}*v_0^{\frac{3}{2}}

Explanation:

Given

f(v) =- cv^\frac{1}{2}

To start with, we begin with

F = ma

Substitute the expression for F

-cv^\frac{1}{2} = ma

-ma = cv^\frac{1}{2}

Acceleration (a) is:

a = \frac{dv}{dt}

So, the expression becomes:

m\frac{dv}{dt} = -cv^\frac{1}{2}

-----------------------------------------------------------------------------------------

Velocity (v) is:

v = \frac{dx}{dt} --- distance/time

v * \frac{dv}{dx}= \frac{dx}{dt}* \frac{dv}{dx}

v * \frac{dv}{dx}= \frac{dv}{dt}

\frac{dv}{dt} = v * \frac{dv}{dx}

--------------------------------------------------------------------------------------------

So, we have:

m\frac{dv}{dt} = -cv^\frac{1}{2}

mv * \frac{dv}{dx} = -cv^\frac{1}{2}

Divide both sides by v^\frac{1}{2}

mv^{1-\frac{1}{2}} * \frac{dv}{dx} = -c

mv^{\frac{1}{2}} * \frac{dv}{dx} = -c

Divide both sides by m

v^{\frac{1}{2}} * \frac{dv}{dx} = -\frac{c}{m}

v^{\frac{1}{2}} * dv = -\frac{c}{m} * dx

Integrate:

\int\limits^v_{v_0} {v^{\frac{1}{2}}} \, dv  = -\frac{c}{m}\int\limits^x_0 {}} \, dx

\frac{2}{3}v^{\frac{3}{2}}|\limits^v_{v_0}  = -\frac{c}{m}x|\limits^x_0

\frac{2}{3}(v^{\frac{3}{2}} - v_0^{\frac{3}{2}} ) = -\frac{cx}{m}

v^{\frac{3}{2}} - v_0^{\frac{3}{2}} = -\frac{3cx}{2m}

v^{\frac{3}{2}} = v_0^{\frac{3}{2}}-\frac{3cx}{2m}

v = (v_0^{\frac{3}{2}}-\frac{3cx}{2m})^\frac{2}{3}

Next, is to get the maximum velocity by distance x.

To do this, we find the derivation by x

\frac{dv}{dx} = 0

\frac{2}{3}(v_0^{\frac{3}{2}}-\frac{3cx}{2m})^{\frac{2}{3} - 1} * -\frac{3c}{2m} = 0

\frac{2}{3}(v_0^{\frac{3}{2}}-\frac{3cx}{2m})^{\frac{2-3}{3}} * -\frac{3c}{2m} = 0

\frac{2}{3}(v_0^{\frac{3}{2}}-\frac{3cx}{2m})^{\frac{-1}{3}} * -\frac{3c}{2m} = 0

(v_0^{\frac{3}{2}}-\frac{3cx}{2m})^{\frac{-1}{3}} * -\frac{c}{m} = 0

Divide both sides by -\frac{c}{m}

(v_0^{\frac{3}{2}}-\frac{3cx}{2m})^{\frac{-1}{3}} = 0

Take cube roots of both sides

(v_0^{\frac{3}{2}}-\frac{3cx}{2m})^{-1} = 0

v_0^{\frac{3}{2}}-\frac{3cx}{2m} = 0

\frac{3cx}{2m} = v_0^{\frac{3}{2}}

x = \frac{2m}{c}*v_0^{\frac{3}{2}}

7 0
3 years ago
In a nuclear fusion reaction, atoms:
spayn [35]

Answer:

Combine to form heavier elements

Explanation:

as opposed to fission which splits heavier atoms into lighter elements.

3 0
3 years ago
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