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poizon [28]
2 years ago
7

Please help im stuck and can't find the answer sheet ANYWHERE :(​ PLEASEEEEEEEEEEE

Physics
1 answer:
Vladimir [108]2 years ago
6 0

Answer:

All steps are 20 * 100  (break the rest into appropriate pieces)

You can multiply as follows

(2000) * ((3 * 60) + (2 * 60) + 60)

V = 2000 * 6 * 60) = 720,000 cm^3 = .72 m^3

.72 m^3 * 2400 kg / m^3 = 1728 kg

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Explanation:

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N2 + O2 → 2NO N-N triple bond: 941 kJ/mol O-O double bond: 495 kJ/mol N-O bond: 201 kJ/mol
kiruha [24]

Answer:

\large \boxed{\text{761 kJ}}

Explanation:

You calculate the energy required to break all the bonds in the reactants.

Then you subtract the energy needed to break all the bonds in the products.

                        N₂  +   O₂   ⟶         2NO

                     N≡N  + O=O ⟶       2O-N=O

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D/kJ·mol⁻¹:     941      495           201      607

\begin{array}{rcl}\Delta H & = & \sum{D_{\text{reactants}}} - \sum{D_{\text{products}}}\\& = & 2 \times 941 +1 \times 495 - (2 \times 201 + 2\times 607)\\&=& 2377 - 1616\\&=&\textbf{761 kJ}\\\end{array}\\\text{The enthalpy of reaction is $\large \boxed{\textbf{761 kJ}}$}.

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I can’t understand I’m sorry but if you need help with math I can help you
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Light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance li
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Answer: 3.142656 × 10^16 feet

Explanation: Given that the

Speed = 982,080,000 ft/s, and

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Since the time is second in one year and speed is ft/s, substitute both into the formula

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distance = 982,080,000 × 32,000,000

Distance = 3.142656 × 10^16 feet.

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