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levacccp [35]
3 years ago
9

If the change in enthalpy is -5074.1 kj , how much work is done during the combustion?

Physics
1 answer:
baherus [9]3 years ago
8 0
Hence, 
<span>∆H = ∆U + W </span>
<span>=> </span>
<span>W = ∆H - ∆U </span>
<span>= -5074 kJ - (-5084.) kJ </span>
<span>= 10 kJ</span>
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