3 years ago

If the change in enthalpy is -5074.1 kj , how much work is done during the combustion?

1 answer:

8 0

Hence,
∆H = ∆U + W 
=> 
W = ∆H - ∆U 
= -5074 kJ - (-5084.) kJ 
= 10 kJ

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3 years ago

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