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Sauron [17]
3 years ago
5

As you watch a surfer ride a wave toward the shoreline what is the shoreline

Physics
2 answers:
snow_lady [41]3 years ago
6 0

Answer:

b. Reference point

Explanation:

A shoreline is the meeting point between a body of water ( say, ocean or river) meet with dry land and hence can be reference point or a frame of reference

Maslowich3 years ago
4 0
B is the answer glad to help
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The pressure on a volume of liquid V = 1.0 mº at the surface is approximately equal to the atmospheric pressure Patm = 1.00 x 10
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Answer:-2.86*10⁻⁴

Explanation: Use the equation change in volume = (change in pressure * original volume) / Bulks Modulus. ΔV = (-Δp*V₀) / B

Plugging in your numbers, you should get ΔV = (-2.29*10⁷*1) / (8*10¹⁰) = -2.86*10⁻⁴

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3 0
3 years ago
Around which months does el nino end and la nina start?
ad-work [718]

Answer:

They both tend to develop during the spring (March-June), reach peak intensity during the late autumn or winter (November-February), and then weaken during the spring or early summer (March-June)

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KatRina [158]
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5 0
4 years ago
A flywheel of J = 50 kg-m2 initially standing still is subjected to a constant torque. If the angular velocity reaches 20 Hz in
Karolina [17]

Answer:

\tau = 1256.5\ N.m

Explanation:

given,

J = 50 kg-m²

frequency, f = 20 Hz

time ,t = 5 s

we know,

angular velocity = 2 π f

ω = 2 π x 20

ω = 125.66 rad/s

now, angular acceleration calculation

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{125.66-0}{5}

   α = 25.13 rad/s²

Torque given to the flywheel.

    \tau = I \alpha

    \tau = 50\times 25.13

    \tau = 1256.5\ N.m

Torque of the given  flywheel is equal to \tau = 1256.5\ N.m

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4 years ago
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