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Sauron [17]
3 years ago
5

As you watch a surfer ride a wave toward the shoreline what is the shoreline

Physics
2 answers:
snow_lady [41]3 years ago
6 0

Answer:

b. Reference point

Explanation:

A shoreline is the meeting point between a body of water ( say, ocean or river) meet with dry land and hence can be reference point or a frame of reference

Maslowich3 years ago
4 0
B is the answer glad to help
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A hoodlum throws a stone vertically downward with an initial speed v0 from the roof of a building, a height h above the ground.
Vaselesa [24]
V2=u2+2as
v2=144+600
v2=744
v=√744
6 0
4 years ago
Q10. Explain the Retention time, in GC. What will happen to retention time, if you increase the detector temperature
nadya68 [22]

Answer:

The detector temperature doesn't affect retention time

Explanation:

Retention time is one of the chromatographic parameters. Is defined as the time of a compound spends from injection to detection.

A solute in GC is added to the injector where is volatilized. When volatilized, it pass through a column until the detector.

The detector temperature doesn't affect retention time. To change retention time you must change injector temperature or column temperature. An increase in column or injector temperature results in a decrease in retention time.

4 0
3 years ago
si tienes 2 circuitos uno en serie y otro en paralelo con el mismo valor en sus resistencias, para cuál circuito la resistencia
Novosadov [1.4K]

Answer:

circuito paralelo

Explanation:

Siempre el circuito en paralelo dara una resistencia menor. Recuerda que las resistencias se suman en el circuito en serie, an cambio en el circuito en paralelo, la corriente se bifurca de manera de circular con mayor intensidad por las ramas que tengan menos resistencia, y tal situacion llevara siempre a producir una menor resistencia equivalente.

5 0
3 years ago
If the density of pure copper is 8.89g/cm3(at 20•c),calculate the volume of a copper brick with a mass of 4.5kg
oksano4ka [1.4K]

The volume of a substance can directly be calculated by the ratio of mass and density. That is:

volume = mass / density

 

Since the mass is 4.5 kg or 4500 grams, therefore:

volume = 4500 g / (8.89 g / cm^3)

<span>volume = 506.19 cm^3</span>

8 0
3 years ago
A 2 kg toy car moves at a speed of 5 m/s. If a child applies a 5N force for 2 m in the same direction the car is already moving,
WITCHER [35]

Answer:

10\: \mathrm{J}

Explanation:

The kinetic energy of an object is KE=\frac{1}{2}mv^2, where m is the mass of the object and v is the velocity of the object.

The toy car's initial kinetic energy is KE_{i}=\frac{1}{2}\cdot 2\cdot 5^2=25\: \mathrm{J}.

After the child applies a 5N force on it in the same direction, its velocity will increase but its mass will stay the same.

To find the final velocity of the toy car, we can use kinematic equation v_f^2=v_i^2+2a\Delta x, \\ v_f=\sqrt{v_i^2+2a\Delta x}

We are given v_i=5\: \mathrm{m/s} and \Delta x = 2\: \mathrm{m}.

To find acceleration:

F=ma, a=\frac{F}{m}=\frac{5}{2}=2.5\: \mathrm{m/s^2}.

Now substitute v_i=5\: \mathrm{m/s}, \: a=2\: \mathrm{m/s^2}, \: \Delta x = 2\: \mathrm{m} into v_f=\sqrt{v_i^2+2a\Delta x} to get v_f\approx 5.92\: \mathrm{m/s}.

Using this, we can find the final kinetic energy of the toy car is KE_f=\frac{1}{2}\cdot 2\cdot 5.92^2.

Thus, the change in kinetic energy is KE_f-KE_i=\frac{1}{2}\cdot2\cdot 5.92^2-\frac{1}{2}\cdot 2\cdot 5^2=\fbox{$10\: \mathrm{J}$} (one significant figure).

4 0
3 years ago
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