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murzikaleks [220]
2 years ago
5

The cost of renting a car for a day is $0.70 per mile plus a $20 flat fee

Mathematics
1 answer:
Andreyy892 years ago
5 0

Answer:

a) y = .70x + 20

-To find this, use the rate as x since it will change based on the number of miles. Since 20 is a flat fee, it can be added at the end as a constant.

b) This graph forms a straight line.

-This is because the answer in a is a linear equation.

c) The slope is .70 and the y-intercept is 20.

-For this one, the y-intercept is always the constant at the end of the equation and the slope is the coefficient of x.



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a box half full of apples weighs 40kg and the same box one fifth full weighs 22kg, what does the box weigh when empty?
ruslelena [56]
1/2 = 40kg
1/5 = 22kg
1/2 = 5/10
1/5 = 2/10
3/10 is the difference between 18kg.
This means 1/10 of the box filled with apples is 6kg.
40 - (5 x 6) = 10kg. The box weighs 10kg alone. 

5 0
3 years ago
Read 2 more answers
Need help please 10 points
Maslowich

πr² = π.5.5 = π25 units² or 78.5 units²

hope it helps...!!!

6 0
2 years ago
What is the solution to the system of equations? (7, 4) (7, startfraction 13 over 3 endfraction) (8, startfraction 14 over 3 end
miss Akunina [59]

The points are (7, 13/3).

Lets simplify the equation,

The equation of first line: y = 1/3 x + 2

the equation of second line: y= 4/3x - 5

Solve the system of equations by elimination,

Multiply equation A by -4 both sides

-4y = -4(1/3x +2)

-4y = -4/3x-8

After eliminating the equation we get,

y = 13/3

So now have to find x

13/3 = 1/3x + 2

Lets multiply above by 3
x = 13-6

x = 7.

Hence the points are (7, 13/3)

Learn more about Quadratic Equation on:

brainly.com/question/1214333

#SPJ4

5 0
1 year ago
Two number cubes are rolled sequentially. What is the probability that the first number cube shows a five and the other number c
nexus9112 [7]

The probability of first number cube shows a five and the other number cube shows an even number is \frac{1}{12}.

Solution:

Two cubes are rolled sequentially.

Sample space when two dies are rolled

                   =\left\{\begin{array}{l}{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)} \\{(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)} \\{(3,1), 3(, 2),(3,3),(3,4),(3,5),(3,6)} \\{(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)} \\{(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)} \\{(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}\end{array}\right\}

Number of sample space = 36

Even numbers getting when two cubes rolled are 2, 4, 6.

First number cube shows a five and the other number cube shows an even number = {(5, 2), (5, 4), (5 6)}

Number of first number cube shows a five and the other number cube shows an even number = 3

Probability of first number cube shows a five and the other number cube shows an even number

                 $=\frac{\text{Number of outcomes}}{\text{Total number of sample space}} $

                $=\frac{3}{36}

                $=\frac{1}{12}

Hence, the probability of first number cube shows a five and the other number cube shows an even number is \frac{1}{12}.

8 0
3 years ago
Depreciation
hammer [34]

Answer:

a) y=-3950\cdot{x}+21500

b) f(x) =21500\cdot{(0.7953)^x}

c) Year 1: Linear $17550, exponential $17099

Year 4: Linear $5700, exponential $8601

d) Exponential model

e) The linear model depreciates the value quicker than exponential model long term around 4 years

Step-by-step explanation:

a) At year 0 the price is 21500 and at year 2 the price is 13600

WE can use points (0,21500) and (2,13600)

We can determine the gradient

m=(13600-21500)/(2-0)=-3950

We can use the point slow formula:

y-y_1=m\cdot{(x-x_1)}

y-21500=-3950\cdot{(x-0)}

y=-3950\cdot{x}+21500

b) We can use the following equation:

f(x) =a\cdot{(1+r)^x}

f(x) is the depreciation value after amount of time t, a is the new value, r is the rate of depreciation and x is the time.

13600=21500\cdot{(1+r)^2}

r=-0.2047

The depreciation rate is 20.47% and is negative because it decreases the new value of the car

c) Year 1:

y=-3950\cdot{1}+21500=17550

f(x) =21500\cdot{(0.7953)^1}=17099

Year 4:

y=-3950\cdot{4}+21500=5700

f(x) =21500\cdot{(0.7953)^4}=8601

d) Year 2

y=-3950\cdot{2}+21500=13600

f(x) =21500\cdot{(0.7953)^2}=13598

3 0
2 years ago
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