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deff fn [24]
3 years ago
6

Hàng ngày ta thấy Mặt trời , Mặt trăng quay quanh Trái Đất, khi đó ta đã lấy vật mốc là

Physics
1 answer:
marshall27 [118]3 years ago
5 0
I’m sorry I don’t understand this language
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Does a photon emitted by a higher-wattage red light bulb have more energy than a photon emitted by a lower-wattage red bulb
Liono4ka [1.6K]

Answer:

The energy of these two photons would be the same as long as their frequencies are the same (same color, assuming that the two bulbs emit at only one wavelength.)

Explanation:

The energy E of a photon is proportional to its frequency f. The constant of proportionality is Planck's Constant, h. This proportionality is known as the Planck-Einstein Relation.

E = h\, f.

The color of a beam of visible light depends on the frequency of the light. Assume that the two bulbs in this question each emits light of only one frequency (rather than a mix of light of different frequencies and colors.) Let f_{1} and f_{2} denote the frequency of the light from each bulb.

If the color of the red light from the two bulbs is the same, those two bulbs must emit light at the same frequency: f_{1} = f_{2}.

Thus, by the Planck-Einstein Relation, the energy of a photon from each bulb would also be the same:

h\, f_{1} = h\, f_{2}.

Note that among these two bulbs, the brighter one appears brighter soley because it emits more photons per unit area in unit time. While the energy of each photon stays the same, the bulb releases more energy by emitting more of these photons.

6 0
3 years ago
Im need some help with this please
hram777 [196]
The answer is D, human.


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3 years ago
QUICK!! What class of leer is shown below?
wlad13 [49]

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3rd class lever

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3 years ago
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Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
kumpel [21]

Answer:\frac{D_A}{v_B-v_A}

Explanation:

Given

car A had a head start of D_A

and it starts at x=0 and t=0

Car B has to travel a distance of D_A and d_a

where d_a is the distance travel by car A in time t

distance travel by car A is

d_a=v_A\times t

For car B with  speed v_B

d_B=D_A+d_a

v_B\times t=D_A+v_A\times t

t=\frac{D_A}{v_B-v_A}

7 0
4 years ago
Question 2: Start-Up
yuradex [85]

Answer:

The car starts moving in the positive direction at x = 0.2 seconds. Initially it moves very little, but it covers a greater distance with each time increment.

Explanation:

7 0
3 years ago
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