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Digiron [165]
3 years ago
5

What needs to happen for a solute to dissolve in a particular solvent?

Chemistry
2 answers:
umka2103 [35]3 years ago
7 0

Answer:

There needs to be a strong interaction between solvent and solute molecules. However, this interaction must be strong enough to disrupt the molecular interactions between the solute molecules.

Explanation:

It is called solute, the chemical compounds that dissolve in another substance. The solvent is the substance into which the solute will be dissolved to form a new product.

Chemical dissolution is the process of dispersing the solute in a solvent, giving rise to a homogeneous solution or mixture. For such a dissolution to occur, an extremely strong chemical bond between the solute and the solvent must occur. However, this bond must be strong enough to separate the bond between the solute molecules.

Andrews [41]3 years ago
3 0
<span>attractions between the solute and solvent molecules must be greater than the attractions keeping the solute together and the attractions keeping the solvent together.

hope this helps and please rate below and if this helped then please thank me on my profile page and i will do the same for you</span>
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How many joules of heat are lost when 150.0 g of steam are cooled from 124. C to 86 C?
Alinara [238K]

 The  amount   of  joules  of heat  that are lost when 150.0 g of steam  are cooled  from 124 °c to 86 °c  is = -11343  joules


 calculation

heat(Q) = mass(m) x specific heat capacity(C) x  change  in temperature     (ΔT)

  where,

Q=? joules

M=150.0 g

C for steam = 1.99 j/g/°c

ΔT= 86°c-124°c = -38°c


Q  is therefore = 150.0 g x  1.99 j/g/°c   x -38°c =-11343 joules


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Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

R_{in} = \frac{0.04}{100}*2000

R_{in} = 0.8

The rate-out

R_{out} = \frac{A}{6000}*2000

R_{out} = \frac{A}{3}

We can say that:

\frac{dA}{dt}= 0.8-\frac{A}{3}

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

\frac{dA}{dt} +\frac{A}{3} =0.8

Integration of the above linear equation =

e^{\int\limits \frac {1}{3}dt } = e^{\frac{1}{3}t

so we have:

e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

C= 12-2.4

C =9.6

Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

A(t) = 2.74

∴ the concentration at 10 minutes is ;

=  \frac{2.74}{6000}*100%

= 0.0456667 %

= 0.046% to three decimal places

7 0
4 years ago
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