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2 years ago

What needs to happen for a solute to dissolve in a particular solvent?

Chemistry

2 answers:

umka2103 [35]2 years ago

7 0

Answer:

There needs to be a strong interaction between solvent and solute molecules. However, this interaction must be strong enough to disrupt the molecular interactions between the solute molecules.

Explanation:

It is called solute, the chemical compounds that dissolve in another substance. The solvent is the substance into which the solute will be dissolved to form a new product.

Chemical dissolution is the process of dispersing the solute in a solvent, giving rise to a homogeneous solution or mixture. For such a dissolution to occur, an extremely strong chemical bond between the solute and the solvent must occur. However, this bond must be strong enough to separate the bond between the solute molecules.

Andrews [41]2 years ago

3 0

<span>attractions between the solute and solvent molecules must be greater than the attractions keeping the solute together and the attractions keeping the solvent together.

hope this helps and please rate below and if this helped then please thank me on my profile page and i will do the same for you</span>

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Why isn't there a lunar eclipse every time Earth is in between the sun and<br> the Moon?

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2 years ago

Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti

gayaneshka [121]

Answer : The value of $K$ for this reaction is, $2.6\times 10^{15}$

Explanation :

The given chemical reaction is:

$CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)$

Now we have to calculate value of $(\Delta G^o)$ .

$\Delta G^o=G_f_{product}-G_f_{reactant}$

$\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]$

where,

$\Delta G^o$ = Gibbs free energy of reaction = ?

n = number of moles

$\Delta G^0_{(HCH_3CO_2(g))}$ = -389.8 kJ/mol

$\Delta G^0_{(CH_3OH(g))}$ = -161.96 kJ/mol

$\Delta G^0_{(CO(g))}$ = -137.2 kJ/mol

Now put all the given values in this expression, we get:

$\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]$

$\Delta G^o=-89.4kJ/mol$

The relation between the equilibrium constant and standard Gibbs, free energy is:

$\Delta G^o=-RT\times \ln K$

where,

$\Delta G^o$ = standard Gibbs, free energy = -89.4 kJ/mol = -89400 J/mol

R = gas constant = 8.314 J/L.atm

T = temperature = $30.0^oC=273+30.0=303K$

$K$ = equilibrium constant = ?

Now put all the given values in this expression, we get:

$-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K$

$K=2.6\times 10^{15}$

Thus, the value of $K$ for this reaction is, $2.6\times 10^{15}$

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3 years ago

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2 years ago

What is occurring when reactants are mixed and heated and liquid collects in the sidearm of the apparatus

olga55 [171]

When reactants are mixed and heated and liquid collects in the sidearm of the apparatus, a chemical reaction is occurring.

<h3>What is a chemical reaction?</h3>

A chemical reaction is said to occur when reactants are combined to form products. We must note that the formation of products is evidenced by;

Appearance of a liquid
Appearance of a gas
Appearance of a solid

Hence, when reactants are mixed and heated and liquid collects in the sidearm of the apparatus, a chemical reaction is occurring.

Learn more about chemical reaction:brainly.com/question/22817140

#SPJ1

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2 years ago