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Neporo4naja [7]
2 years ago
15

Free po ints free po ints free p oints free po ints

Chemistry
2 answers:
Zepler [3.9K]2 years ago
8 0
Thanks

Thanks

Thanks

Thanks
Mumz [18]2 years ago
4 0

Answer:

thank you

thank you

thank you

thank you

Explanation:

:)

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A 35 L tank of oxygen is at 315 K with an internal pressure of 190 atmospheres. How
nata0808 [166]

Answer:

600.7 moles

Explanation:

Applying,

PV = nRT................... Equation 1

Where P = Pressure of oxygen, V = Volume of oxygen, n = number of moles, R = molar gas constant, T = Temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

From the question,

Given: P = 190 atm, V = 35 L, T = 135 K

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

n = (190×35)/(135×0.082)

n = 600.7 moles of xygen

6 0
3 years ago
List the two factors used to calculate force ? (20 pionts)
Yuliya22 [10]

Answer:The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other.

Explanation: i hope it answers your question

5 0
3 years ago
Read 2 more answers
This green solution of chromium(III) can further be reduced by zinc metal to a blue solution of chromium(II) ions. Write the bal
Contact [7]

Answer:

Half-reactions:

Cr³⁺ + 1e⁻ → Cr²⁺; Zn → Zn²⁺ + 2e⁻

Net ionic equation:

2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺

Explanation:

The Cr³⁺ is reduced to Cr²⁺:

<h3>Cr³⁺ + 1e⁻ → Cr²⁺ -Half-reaction 1-</h3>

Zn is oxidized to Zn²⁺:

<h3>Zn → Zn²⁺ + 2e⁻ -Half-reaction 2-</h3>

Twice the reduction of Cr:

2Cr³⁺ + 2e⁻ → 2Cr²⁺

Now this reaction + Oxidation of Zn:

2Cr³⁺ + 2e⁻ + Zn → 2Cr²⁺ + Zn²⁺ + 2e⁻

<h3>2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺ - Net ionic equation</h3>

6 0
2 years ago
To three significant digit,what is the mass percentage of iron in the compound Fe2O3​
svlad2 [7]

69.9%

Explanation:

To find the mass percentage of iron in the compound in Fe₂O₃, we would go ahead to express the given molar mass of the iron to that of the compound.

 Mass percentage  = \frac{molar mass of Fe}{Molar mass of Fe_{2}O_{3}  }  x 100

Molar mass of Fe = 55.85g/mol

Molar mass of O = 16g/mol

Molar mass of Fe₂O₃ = 2(55.85) + 3(16) = 159.7‬g/mol

Mass percentage  = \frac{2(55.85)}{159.7}  x  100   = 69.94% = 69.9%

learn more:

Mass percentage brainly.com/question/8170905

#learnwithBrainly

4 0
3 years ago
What does a biochemical solar panel have
Viktor [21]
I agree with the person on top have a beautiful day:)
4 0
3 years ago
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