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2 years ago

Free po ints free po ints free p oints free po ints

Chemistry

2 answers:

Zepler [3.9K]2 years ago

8 0

Thanks

Thanks

Thanks

Thanks

Mumz [18]2 years ago

4 0

Answer:

thank you

Explanation:

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¿Cuál de las siguientes NO es una característica de los ácidos?

Serga [27]

Answer: B

Explanation: La respuesta es b porque su electricidad y no es un ácido.

4 0

2 years ago

2. The Food and Drug Administration (FDA) mandates that all vinegar sold in the United States must have a minimum concentration

Scilla [17]

Answer:

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

Explanation:

4% acetic acid by mass means that 4 gram of acetic acid in 100 g solution.

Given that density of the vinegar is same is that of water = 1 g/mL

Mass of the vinegar solution = 100 g

Volume of the vinegar solution = V

$Density=\frac{Mass}{Volume}$

$1 g/mL=\frac{100 g}{V}$

V = 100 mL = 0.1 L

Moles of acetic acid = $\frac{4 g}{60.052 g/mol}=0.0666 mol$

$Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}$

$M=\frac{0.0666 mol}{0.1 L}=0.6660 mol/L$

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

4 0

3 years ago

If you were preparing a defined, minimal medium for an aerobic, chemolithotrophic bacterium to grow on, which of the following c

Eddi Din [679]

Answer:

I believe it's D. FE2+ and MgCl2...

Explanation:

Hope this helps!!

7 0

2 years ago

A certain alcohol contains only three elements, carbon, hydrogen, and oxygen. Combustion of a 60.00 gram sample of the alcohol p

marin [14]

Answer:

$C_2H_6O$

Explanation:

The first step is the calculation of the moles of $H_2O$ and $CO_2$ , so:

$114.6~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=2.6~mol~of~CO_2$

$70.44~g~H_2O\frac{1~mol~H_2O}{18~g~H_2O}=~3.9~mol~H_2O$

Now, in 1 mol of CO2 we have 1 mol of C and in 1 mol of $H_2O$ we have 1 mol of H. Additionally, if we want to calculate the moles of oxygen we need to calculate the grams of C and O and then do the substraction form the initial amount, so:

$2.6~mol~CO_2\frac{1~mol~C}{1~mol~CO_2}\frac{12~g~C}{1~mol~C}=31.25~g~of~C$

$3.9~mol~H_2O\frac{2~mol~H}{1~mol~H_2O}\frac{1~g~H}{1~mol~H}=7.82~g~of~H$

$Total~grams=~31.25~+~7.82=39.08~g$

$grams~of~O=60.00~g-~39.08~g=20.92~g~of~O$

Now we can convert the grams of O to moles, so:

$20.92~g~of~O\frac{1~mol~O}{16~g~O}=1.30~mol~O$

The next step is to divide all the mol values by the smallest one:

$O=\frac{1.30~mol~O}{1.30~mol~O}=~1$

$C=\frac{2.6~mol~C}{1.30~mol~O}=~2$

$H=\frac{7.82~mol~H}{1.30~mol~O}=6$

Therefore the formula is $C_2H_6O$

6 0

3 years ago

2,6 -dimetil nonano 4 etil-2,2dimetil-4-propo:0ctano

Svetllana [295]

Answer:

it will be 26 %t _4

Explanation:

do the math and tst

7 0

2 years ago