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Neporo4naja [7]
2 years ago
15

Free po ints free po ints free p oints free po ints

Chemistry
2 answers:
Zepler [3.9K]2 years ago
8 0
Thanks

Thanks

Thanks

Thanks
Mumz [18]2 years ago
4 0

Answer:

thank you

thank you

thank you

thank you

Explanation:

:)

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How do the properties of elements in the same column of the periodic table compare
Alik [6]
The columns of the periodic table, also referred to as "groups" contain elements with similar reactive properties, due to these elements having a similar configuration of electrons in their outer shell.
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3 years ago
Pls do it I don’t understand
Ann [662]
The first question's answer is

6 0
2 years ago
Calcium oxide and oxygen gas are produced by the thermal decomposition of limestone in the reaction CaCO (s) CaO(s) + CO (g). Wh
kozerog [31]
The mass of lime that  can  be produced  from  4.510 Kg of limestone  is calculated  as  below

calculate the moles  of CaCO3  used

that is  moles =mass/molar mass
convert  Kg  to g  = 4.510 x1000 =4510g
=  4510 / 100 =45.10 moles
CaCO3 = CaO  +O2

by use of mole ratio between CaCO3  to CaO  (1:1) the  moles of CaO  is also= 45.10 moles
mass of CaO = moles x molar  mass

45.10  x56 = 2525.6  g  of  CaO



6 0
4 years ago
Read 2 more answers
g A microwave oven heats by radiating food with microwave radiation, which is absorbed by the food and converted to heat. If the
Sliva [168]

Answer:

The total photons required = 5.19 × 10²⁸ photons

Explanation:

Given that:

the radiation wavelength λ= 12.5 cm = 0.125 m

Volume of the container = 0.250 L = 250 mL

The density of water = 1 g/mL

Density = mass /volume

Mass =  Volume ×  Density

Thus; the mass of the water =  250 mL ×  1 g/mL

the mass of the water = 250 g

the specific heat of water s = 4.18 J/g° C

the initial temperature T_1 = 20.0° C

the final temperature T_2 = 99° C

Change in temperature \Delta T = (99-20)° C = 79 ° C

The heat q absorbed during the process = ms \Delta T

The heat q absorbed during the process = 250 g × 4.18 J/g° C × 79° C

The heat q absorbed during the process = 82555 J

The energy of a photon can be represented by the equation :

= hc/λ

where;

h = planck's constant = 6.626 \times 10^{-34} \ J.s

c = velocity of light = 3.0 \times 10^8 \ m/s

=  \dfrac{6.626 \times 10^{-34} \times 3.0 \times 10^8}{0.125}

= 1.59024 \times 10^{-24} J

The total photons required = Total heat energy/ Energy of a photon

The total photons required = \dfrac{82555 J}{1.59024 \times 10^{-24}J}

The total photons required = 5.19 × 10²⁸ photons

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3 years ago
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