Answer:
isentropic efficiency = 0.818
Explanation:
given data
pressure P1 = 95 kPa
temperature = 27°C
pressure P2 = 600 kPa
temperature = 277°C
to find out
isentropic efficiency of the compressor and exit temperature of the air
solution
we know from ideal gas of properties of air is
Pr1 at 27°C = 1.3860
and h1 at 300 K = 300.19 kJ/kg
and h2 at 550 K = 555.74 kJ/kg
and
we know equation for isentropic process that is
.........................1
put here value we get
solve we get Pr2
Pr2 = 8.75
by ideal gas of properties of air will be at Pr2
h2s = 508.66
T2s = 505.5 K
'so
isentropic efficiency will be here as
isentropic efficiency =
isentropic efficiency =
isentropic efficiency = 0.818
Answer:
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Answer: Collect more information about the extent to which this reported behavior is impacting others
Explanation:
The options are:
a. Collect more information about the extent to which this reported behavior is impacting others.
b. Tell the CEO about what you have uncovered and ask for her permission to speak about it with the CFO.
c. Focus on the CFO’s work performance since his personal behavior is inappropriate in the workplace.
d. Inform the human resources department that there is a potential problem.
Given the information provided in the question, the most effective next step in the process will be to collect more information about the extent to which this reported behavior is impacting others. This will be vital in determining whether what is being said about the Chief Financial Officer is true or not and also to know if true, whether it has an affect on the performance of affected employees in the organization.
Option B is wrong as telling the CEO right away isn't the next step as adequate information must be gathered first.
Option C is also wrong as the focus shouldn't be on his work in the organization alone. His personal behavior should be addressed as well if he's wrong. A great organization is made up of great individuals with good behaviors.
Option D is also wrong as the next step should not be to inform the human resource.
Therefore, the correct option is A.
Answer:
(a) 185.1002 lbm/min
(b) 7125.12 Btu/min
(c) 0.42
Explanation:
Here we have;
= 6
γ = 1.4 for air
T₁ = 460 R = 255.56 K
T₃ = 700 R = 388.89 K
1 ton of refrigeration capacity = 3.52 kWh = 0.98 W
∴ 15 ton = 15×3.52 = 52.8 kW/h
= 189910.0534716 kJ/h = 3165.1676 kJ/min
T₂ = 1.669 × 460 = 767.515 R = 426.4 K
Refrigeration effect per kg = 1 × × (T₃ - T₂) = 1.005 × (700 - 767.515) = 67.85 = 37.7 kJ/kg
83.96 kg/min = 185.1002 lbm/min
(b)
T₄ = T₃×1.669 = 700×1.669 = 1167.96 °R = 648.9 K
= 21925.83 kJ/min
= 14408.4 kJ/min
= 21925.83 - 14408.4 = 7517.43 kJ/min
1 kW = 56.87 Btu/min
Therefore;
125.29 kW = 7125.12 Btu/min
(c) The coefficient of performance (COP), is given by the relation;