Answer:
Unit testing is a software development process in which the smallest testable parts of an application, called units, are individually and independently scrutinized for proper operation. This testing methodology is done during the development process by the software developers and sometimes QA staff. The main objective of unit testing is to isolate written code to test and determine if it works as intended.
Unit testing is an important step in the development process, because if done correctly, it can help detect early flaws in code which may be more difficult to find in later testing stages.
Unit testing is a component of test-driven development (TDD), a pragmatic methodology that takes a meticulous approach to building a product by means of continual testing and revision. This testing method is also the first level of software testing, which is performed before other testing methods such as integration testing. Unit tests are typically isolated to ensure a unit does not rely on any external code or functions. Testing can be done manually but is often automated. It might be helpful
Answer: 1.98 × 10^4 N
Explanation:
Form similar triangle ADE and ABC
a/x= 2/3, a=2/3x
Width of the strip w= 2(4+a) = 8+2a
W= 8 +2 (2/3x)= 8+4/3x
Area of the strip = w Δx
(8 +4/3x) Δx
Pressure on the strip p= pgx= 10^3 ×9.81x= 9810x
But,
Force= Pressure × area= 9810x × (8+4/3x)Δx
Adding the forces and taking lim n to infinity
F total= lim n--> infinity E 9810x × (8+4/3x)Δx
Ftotal= Integral 2,0 9810x × (8+4/3x)Δx
F total= 9810 integral 2, 0 (8+4/3x)dx
= 9810(8+x^2/2 + 4/3x^3/3)2,0
=9810(4x^2 + 4/9x^3)
=9810(4x2^2 + 4/9×2^3-0)
=9810(16 + 32/9)
Hydrostatic force as an integral
Ft= 19.18 ×10^4N
Answer:
Geological and civil engineers sometimes work together, but have very different responsibilities. While geological engineers study the earth's inner and outer surface to evaluate potential mining and infrastructure construction sites, civil engineers design the infrastructure to be built.
Resisitivty = RA/L = 7*10^-8 ohm meters
Conductivity is the inverse= 14.3*10^6 S/m
Answer:
a) 
b) 
Explanation:
From the properties of Super-heated Refrigerant 134a Vapor at 
, 
; we obtain the following properties for specific enthalpy and specific entropy.
So; specific enthalpy 
specific entropy 
Also; from the properties of saturated Refrigerant 134 a vapor (liquid - vapor). pressure table at 
; we obtain the following properties:
Given that the power input to the compressor is 2 hp;
Then converting to Btu/hr ;we known that since 1 hp = 2544.4342 Btu/hr
2 hp = 2 × 2544.4342 Btu/hr
2 hp = 5088.8684 Btu/hr
The steady state energy for a compressor can be expressed by the formula:
By neglecting kinetic and potential energy effects; we have:
b) To determine the entropy generation; we employ the formula:
In a steady state condition 
Hence;
![\sigma _c = [200 \ lb/hr (0.2157 -0.2315) \ Btu/lb .^0R - \dfrac{(-3730.8684 \ Btu/hr)}{(40^0 + 459.67^0)^0R}]](https://tex.z-dn.net/?f=%5Csigma%20_c%20%3D%20%5B200%20%5C%20lb%2Fhr%20%280.2157%20-0.2315%29%20%5C%20Btu%2Flb%20.%5E0R%20%20-%20%5Cdfrac%7B%28-3730.8684%20%5C%20Btu%2Fhr%29%7D%7B%2840%5E0%20%2B%20459.67%5E0%29%5E0R%7D%5D)
![\sigma _c = [(-3.16 ) \ Btu/hr .^0R + (7.4667 ) Btu/hr ^0R}]](https://tex.z-dn.net/?f=%5Csigma%20_c%20%3D%20%5B%28-3.16%20%29%20%5C%20Btu%2Fhr%20.%5E0R%20%20%2B%20%287.4667%20%29%20Btu%2Fhr%20%5E0R%7D%5D)
