Explanation:
Given that,
Length of the spring, l = 50 cm = 0.5 m
Mass connected to the end, m = 330 g = 0.33 kg
The mass is released and falls, stretching the spring by 30 cm before coming to rest at its lowest point. On applying Newton's second law, 10 cm below the release point, x = 15 cm
(a) When the mass is connected, the force of gravity is balanced by the force in spring.
(b) The amplitude of the oscillation will be 15 cm as it is half of the total distance travelled.
(c) The frequency of the oscillation is given by :
Hence, this is the required solution.
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Hi there!
We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.
There is NO initial vertical velocity, so:
Rearrange to solve for time:
Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)
Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:
In series with the circuit, so for it pass the current to be mensured.
Letter A
If you notice any mistake in my english, please let me know, because i am not native.
The surface area of the smaller pyramid is determined as 42.7 cm².
<h3>
Area of pyramids</h3>
The base area of the two similar pyramid is given as follows;
Base area of large pyramid = 16 cm²
Base area of smaller pyramid = 12.2 cm²
<h3>
Surface area of the similar pyramids</h3>
The surface area of the smaller pyramid is calculated as follows;
s₁/b₁ = s₂/b₂
s₁/12.2 = 56/16
s₁ = 42.7 cm²
Thus, the surface area of the smaller pyramid is determined as 42.7 cm².
Learn more about base area of pyramids here: brainly.com/question/16060915
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