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3 years ago

A baseball player throws 4 balls every 20 seconds. what is his throw frequency

Physics

1 answer:

frosja888 [35]3 years ago

3 0

Answer:

Frequency, f = 0.2 Hz

Explanation:

We have,

A baseball player throws 4 balls every 20 seconds.

It is required to find the frequency of the baseball.

Frequency of an object is defined as the number of times an event occurs. It is given by number of throws per unit time. It can be given by :

$f=\dfrac{4}{20}\\\\f=0.2\ Hz$

So, the frequency of his throw is 0.2 Hz.

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2 years ago

what is the maximum speed of a 34-g object bouncing on a spring (k=78.1 N/m) with an amplitude of 3.5-cm?

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Answer:

The maximum speed of the mass is 1.67 m/s.

Explanation:

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Mass of object is 34 g or 0.034 kg

Spring constant of the spring is 78.1 N/m

Amplitude attained by the object is 3.5 cm or 0.035 m

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3 years ago

A 78 kg skydiver can be modeled as a rectangular "box" with dimensions 24 cm × 35 cm × 170 cm . If he falls feet first, his drag

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Answer:

The terminal speed of his is 137.68 m/s.

Explanation:

Given that,

Mass of skydiver = 78 kg

Area of box $A =24\times35=840\ cm$

Drag coefficient = 0.80

Density of air $\rho= 1.2\times kg/m^3$

We need to calculate the terminal velocity

Using formula of drag force

$F_{d} = \dfrac{1}{2}\rho v^2Ac$

Where,

$\rho$ = density of air

A = area

C= coefficient of drag

Put the value into the formula

$78\times9.8=\dfrac{1}{2}\times1.2\times v^2\times24\times10^{-2}\times35\times10^{-2}\times0.80$

$v^2=\dfrac{2\times78\times9.8}{1.2\times24\times10^{-2}\times35\times10^{-2}\times0.80}$

$v=\sqrt{\dfrac{2\times78\times9.8}{1.2\times24\times10^{-2}\times35\times10^{-2}\times0.80}}$

$v=137.68\ m/s$

Hence, The terminal speed of his is 137.68 m/s.

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