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2 years ago

A baseball player throws 4 balls every 20 seconds. what is his throw frequency

Physics

1 answer:

frosja888 [35]2 years ago

3 0

Answer:

Frequency, f = 0.2 Hz

Explanation:

We have,

A baseball player throws 4 balls every 20 seconds.

It is required to find the frequency of the baseball.

Frequency of an object is defined as the number of times an event occurs. It is given by number of throws per unit time. It can be given by :

$f=\dfrac{4}{20}\\\\f=0.2\ Hz$

So, the frequency of his throw is 0.2 Hz.

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The Pacific Plate is moving 29 mm/year toward the north and 20 mm/year toward the west relative to the North American Plate. Sho

adell [148]

Answer:

7 mm per year

Explanation:

It is given that :

The Pacific plate is moving towards north at = 29 mm per year

The Pacific plate is moving towards west at = 20 mm per year

We have to calculate the total relative motion towards the northwest.

So we have to find the resultant of the two motions.

Since the two movements are perpendicular, therefore the angle between the two motions is 90 degree.

Therefore, finding their resultant,

$R^2=(29)^2+(20)^2$

$R^2=(49)^2$

R = 7

Therefore, total relative motion towards the northwest is 7 mm per year.

4 0

2 years ago

A potato is shot out of cylinder at an angle of 17 degrees above the horizontal with an initial speed of 20 m/s. What is its max

madreJ [45]

Answer:

Maximum height, h = 1.74 meters

Explanation:

It is given that,

A potato is shot out of the cylinder. It is a case of projectile motion. The potato makes an angle of 17 degrees above the horizontal.

Initial speed with which the potato is shot out, u = 20 m/s

We have to find the maximum height of the potato. The maximum height of a projectile (h) is given by the following formula as :

$h=\dfrac{u^2sin^2\theta}{2g}$

Where

$\theta$ = angle between the projectile and the surface

g = acceleration due to gravity

$h=\dfrac{(20\ m/s)^2sin^2(17)}{2\times 9.8\ m/s^2}$

h = 1.74 m

or h = 1.74 meters

Hence, this is the required solution.

8 0

2 years ago

You drop a ball from a height of 2.0 m, and it bounces back to a height of 1.5 m. (a) what fraction of its initial energy is los

Scilla [17]

a) At a position of 2.0m, the Initial energy is all made up of the potential energy=m*g*hi
and meanwhile at 1.5 all its energy is also potential energy=m*g*hf

The percentage of energy remaining is E=m*g*hi/m*g*hf x 100

and since mass and gravity are constant so it leaves us with just E=hi/hf
which 1.5/2.0 x100= 75% so we see that we lost 25% of the energy or 0.25 in fraction

b) Here use the equation vf^2=vi^2+2gd

where g is gravity, vf is the final velocity and vi is the initial velocity while d is the distance travelled

so in here we are looking for the vi so let us isolate that variable
we know that at maximum height or peak, the velocity is 0 so vf is 0

therefore,

vi =sqrt(-2gd) 
vi =sqrt(-2x-9.81x1.5) 
vi =5.4 m/s

c) The energy was converted to heat due to friction with the air and the ground.

6 0

2 years ago

A child throws a ball vertically upward to a friend on a balcony 28 m above him. The friend misses the ball on its upward flight

photoshop1234 [79]

Answer:

$t=1.9 sec$

Explanation:

From the question we are told that:

Height $h=28m$

Time $t=3s$

Generally the Newton's equation for Initial velocity upward is mathematically given by

$s=ut+\frtac{1}{2}at^2$

$28=3u-\frac{1}{2}*9.8*3^2$

$u=24.03m/s$

Generally the velocity at elevation and depression occurs as ball arrives and passes through S=28

$v=\sqrt{24.03-2*9.8*28}$

$v=5.35m/s and -5.35m/s$

Generally the Newton's equation for time to reach initial velocity is mathematically given by

$v=u+at$

$5.35=24.03-9.8t$

$t=\frac{28.03-5.35}{9.8}$

$t=1.9 sec$

4 0

2 years ago

Which of the following concepts best explains why a mass of low-density material in the mantle rises?Multiple Choice Strain Buoy

SOVA2 [1]

Answer:

Bouyancy

Explanation:

Bouyancy occurs when the upthrust exerted on an object is equal to the weight of object displaced. It is mostly applicable to low density objects for example balloon. When balloon is displaced in water, it floats. This is due to the effect of the upthrust acting on the balloon which allows the balloon to float and which is opposite the weight.

Note that the weight acts downwards the object while the upthrust always acts opposite (upward)

8 0

2 years ago